Would anyone be able to shed some light on the method for how - 4ChanArchives : a 4Chan Archive of /wsr/

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Would anyone be able to shed some light on the method for how

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Anonymous
2016-02-11 23:23:02 Post No. 55152
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Anonymous 2016-02-11 23:23:02 Post No. 55152 [Report]

Would anyone be able to shed some light on the method for how one would go about doing this?

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Anonymous 2016-02-11 23:30:10 Post No.55158
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Anonymous 2016-02-11 23:30:10 Post No.55158 [Report]

>>55152
9k=3+k

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Anonymous 2016-02-11 23:34:05 Post No.55165
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Anonymous 2016-02-11 23:34:05 Post No.55165 [Report]

>>55152
The function is defined in two parts. In order to make it continuous, you just have to make the two parts meet.

They split in x=3.

So, in x=3, the two parts need to have the same value.

Which means that:
k*32=3+k

Which leads to:
k=3/8

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Anonymous 2016-02-11 23:43:10 Post No.55168
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Anonymous 2016-02-11 23:43:10 Post No.55168 [Report]

>>55165
fixing :

k*3^2 = 3 + k
9k = 3 + k (as in >>55158)
8k = 3
k = 3/8

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Anonymous 2016-02-11 23:51:00 Post No.55178
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Anonymous 2016-02-11 23:51:00 Post No.55178 [Report]

Thank you

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