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Math problem

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Hey guises?
Wanna do some math?
Got some basic Calculus question for you.=^)
Try them if you got them skillz

Protip: Hospital rule.
GLHF =^)
>>
first Lim is Pi btw
>>
Every day this site is becoming more cancerous
>>
2)
cos(sqrt(x))^(3/x)
= exp((3/x)*ln(cos(sqrt(x))))
= exp((3/x)*ln(1-x/2 + o(x)))
= exp((3/x)*(-x/2)+o(x))
lim (x ->0) = exp(-3/2)
>>
>>49750

In the third one, replace tan x with its Taylor polynomial approximation: tan x = x + x^3 / 3 + ..., so tan x / x = 1 + x^2 / 3 + ..., and replacing 1/x^2 with n, you get (1 + (1/3) * (1/n))^n, the limit of which is e^(1/3)
Thread replies: 5
Thread images: 1

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