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Trigonometry problem


Thread replies: 5
Thread images: 1

Hi everyone.

Pic related. The answer should be 500m^2. I don't know how to calculate this. Could someone explain the method?
>>
>>148980
Didn't bothering looking for an easier method.
Split BCD into two right angles then work out the area of both.
>>
>>149001
That advice isn't helpful.
>>
I solved it. Have a nice day everyone.
>>
>>148980
Use law of sines (http://www.sparknotes.com/testprep/books/sat2/math2c/chapter9section9.rhtml) to find angles and third edge.

Bisect into two right-triangles.

1/2*base*height.
Thread replies: 5
Thread images: 1
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