How the fuck do you go from (x^3+6x)-385 to (x-7)(x^2+7x+55) ??
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How the fuck do you go from
(x^3+6x)-385
to
(x-7)(x^2+7x+55) ??
It looks like an advanced form of factoring.
I haven't done this form of differentials in a long time; the result is right [f'(x) = (3x+2) + 6], but where does the infinitesimal (dx, delta x) show up in this problem?
>>147729
f'(x) = (3x^2) + 6
I meant
>>147620
it looks like they factored out the (x-7) to cancle out the one on the bottom.
Thats a bad approach.
instead, just use long division to divide the (x^3+6x-385) by (x-7).
>>147734
This.