>>8174962
floor(-2)+floor(--2)=0
looks good to me

I think you're right. You can always split the limit up into two parts and it look like the first is -2 and the latter is 2.

Bumpé

It's -1. Take the limit from both sides on the intervals the step functions are constant.

>>8174982
That only works when both functions have an existing limit at the point of interest. A lone step function never has an existing limit at integers, so this method will not work at all.

If you study the limit to the left of the x=-2(which means x<-2), then the limit is: (-3 +2)=-1
When you study the limit to the right in the x=-2, that is : (-2+ 1)=-1. The limit is -1, cause the limits to the left and right are equal. Be more careful next time i guess.

>>8175033
How the fug did you get -1 I don't even get how you could get anything BUT zero

>>8174962
IT's -1, is not that hard to figure out. You have to study it to the left and to the right of -2.

>>8175039
In order to figure out how to solve it, just think about something simpler. The limit to the left of 1 for [x] is 0, cause you get as close as possible to 1 but not in that value. On the other hand, the limit to the right of 1 for [x] is 1, cause you never get less that 1 as close as you get to that value.

>>8175040
Add the value of both step functions on the interval (-3,-2) and then on (-2,-1). You will notice that the sum is in both cases -1, and since the sum of the step functions exhibits this constant behavior in a local interview of the point -2, the limit is also -1.

Yep I see it now. Fuck