which calculation is this number the result of?
answer fits into one post, no picture as answer allowed.
>>8169862
It could be anything
>>8169862
that number + 0 = that number
>>8169862
Judging from all the 0's at the end, I'd say it's something like "what is the smallest number divisible by every element in the set "blah" where blah is a certain subset of natural numbers. Actually, I think all the 0's at the end might be able to tell us that, but fuck counting.
It's probably a factorial that can be worked out to some extent by counting the number of 0s which correspondes to the number of factors of 5s
>>8169873
Or indeed using stirlings formula
2 prime numbers multiplied
>>8169862
Why not make a textfile first and let bored mathfags work it out?
>>8169862
Looks like some factorial
>>8169942
number is too large to fit into single post
solution can be written down in less than 20 digits
>>8169932
ayy it's 1243! for you autists
pic not related
>>8169958
>1243!
how did you solve that?
I recognized the number as a factorial from the string of 0s at the end, just checked all factorials up to 2000 with a small matching string
>>8169971
why is there a string of zeros at the end of a factorial?
>>8169862
Let me just head on to OIES real quick
shit I have to type all this out
>>8170001
You keep ending up with multiples of even numbers and 5s. Every even number and a five will result in another ten. And you can never go back.
>>8170001
Because everytime you multiply by a multiple of 10 you get a zero that does not go away
>>8169958
no its not
Can't you make an estimate of the interval that factorial is between based on the amount of zeroes it has? like, 10! has 2 zeroes because it multiplies by 10 and then by (2*5) again, 20! has 4 zeroes since it does that again, 30! has 7 for some reason, but still. Idk someone smart do the squigly lines and work it out pls
>>8170167
shit nvm I thought you said 1234!
>>8170182
Well you got it. Ever two zeroes is another multiple of ten. Better precision, ever 5 will have at least 2 even numbers that preceded it, so every 5 will have contributed another 0. You could get any factorial within +/- 2.5 of the right number.
>>8169962
OP said it was a short expression and the number of zeros at the end suggests it's some kind of repeated multiplication with a lot of terms 5 or 10. so probably a factorial.
If you count the zero you can find a small range of possible values. there's 307 trailing zeros, which mean it has been multiplied by 10 at least 307/2 times which means the number you're looking for is less than 1500! You can count that better if you consider that 25 contains 5 twice, and stuff like that but I can't be bothered with proper combinatorics so late in the night
I also got 1243, counted the digits of the number (using GIMP) then used stirlings approximation and found the solution to nln n -n = ln c. Where is the given number and used it's first 4 digits times by 10^digit.
>>8169862
How would I know and why would I care
>>8170013
>And you can never go back.
Course you can Pedro
>>8169862
how many zeros at the end pls
>>8169872
Number-1 + 1 ?
>>8169862
the number is equal to 1250!
>>8171710
sorry rather 1241!
