Probability problem
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i have to advance in probability and i'm stuck in this frustrating question.
one Student is tested in 2 tests,the probability from him to pass the first test is 65%.and the probability for him to pass both tests is 55%,and the probability for him to pass at least one test is 80%.
the part which im having trouble with is that 80% chance ,let A be the probability to pass the first test and let B be the probability to pass the second test, now from what i understood from the given is that
P(A ∩ B')+P(A' ∩ B)=80%.
is that correct?
>>8152423
thank you i thought the same but im still having trouble finishing up my probability table ,if you know what i mean.
>>8152423
Never mind if you don't,but can you give me your way of finding the probability for the student to pass the second test?
>>8152414
That's incorrect. The probability for him to pass at least one test is P(A ∩ B') + P(A' ∩ B) + P(A ∩ B)
P(A ∩ B') + P(A' ∩ B) is the chance of him passing exactly one test.
The rest is simple algebra.
>>8152510
I am triggered
>>8152510
wow thanks bro you have no idea how much you've helped!!
>>8152414
Aren't you missing the probability of passing both tests?
i.e. P(A ∩ B')+P(A' ∩ B)+P(A ∩ B)=80%
>>8152572
welp, guess I should have read the thread first.
next time post in the sqt
>>8152572
Yes i was missing that,Thanks for your help i've solved the question.
Thank you anons OP here ,you are the only ones I've got.
