If a container has 1 liter of water in it, how big the hole at the bottom is if it takes 24h for it to drip out?
the size of your mums anus
>>8080452
He said hours not seconds
>>8080448
need the height of the container to solve it
>>8080589
We assume the containers a perfect cube
>>8080606
still need the height
>>8080608
*sigh* 10cm
>>8080448
What is the local gravity?
>>8080612
well we know flow rate = velocity x area
we got flow rate 1L/24hrs = 1.572e-8 m3/s
we get velocity from bernoulis principle
[(v1)^2]/2 + gz1 + P1/p1 = [(v2)^2]/2 + gz2 + P2/p2
v = velocity
g = gravity
z = height
P = pressure
p = density
we take reference point 1 as top of container
so v1 = 0 since water at top is pretty much not moving, P1 = P2 = atmospheric pressure, p1 = p2 since incompressible fluid, z2 = 0, z1 = 0.1m
so final eq is
gz1 = [(v2)^2]/2
v2 = 1.401 m/s
so area of hole = q/v = 1.122e-8 m2
hole radius = (area/pi)^(1/2) = 5.976e-5 m
>>8080448
4 light years.
>>8080608
No you don't. The size of the hole is dependent on the side lengths of the cube.
>>8080448
level?
closed container?
pressure loss negligible?
speed of fluid IN container negligible?
aperture level?
shape of aperture?
spin flow in aperture?
referring to Oh*Re >= const. ?