Anyone knows how to solve the convergence of this integral ?
[eqn] 1 - x^4 \geq 1 - x [/eqn]
[eqn] \sqrt{1 - x^4} \geq \sqrt{1 - x} [/eqn]
[eqn] \frac{1}{\sqrt{1 - x^4}} \leq \frac{1}{\sqrt{1 - x}} [/eqn]
[eqn] \int_0^1 \frac{1}{\sqrt{1 - x^4}} dx \leq \int_0^1 \frac{1}{\sqrt{1 - x}} dx = \int_0^1 \frac{1}{\sqrt{x}} dx = 2[/eqn]
>>8070862
>>8070910
How can i see it?
>>8070916
When gookmoot fucking fixes LaTeX
>>8070916
>>8070862
>>8070923
got you senpai
>>8070930
Thank you so much
>>8070910
Nigger.
Dish antenna transistor would help
>>8071712
>>8071712
Nigga
>>8072030
Nigga
>>8072030
You're clicking on the wrong one you idiot. Click on the one next to the pushpin. Jesus Christ.
