JUST
>>8062440
Is that supposed to be difficult?
>>8062447
for kids like OP, yeah
F = kx
Fc = (mv^2)/r
Wow 2 equations op so hard
>>8062440
well you know the radius of a circle is pir^2. so you have the circumference now. the squiggly w looks like roughly 45 degrees so thats just an eigth of the area. now to find the area of the sin wave you just take the integral from m to the radius. whats so hard?
>>8062563
>the squiggly w looks like 45 degrees
>>8062440
r''(t) = -k/m*(r(t)-R) + w^2 / r(t)
>>8062563
>radius of a circle is pir^2
>>8062563
>squiggly w
You bring shame to this board
>>8062567
>>8062652
>>8062667
>> Falling for that bait
>>8062567
lol yo shutup
>>8062710
>le epin bate
Take it to /r9k/
Just post the circumference
>>8062563
>squiggly w
[eqn]L=\frac{M}{2}(r\dot{\theta})^2 - kr^2/2 [/eqn]
solv'd
>>8062830
assuming its vertically oriented too
[eqn]L=\frac{M}{2}(r\dot{\theta})^2 - kr^2/2 - Mgr\sin\theta[/eqn]
Given M,k,w find R
>>8063378
>what is the equilibrium length
>>8062830
Question
When a term has a dot over it, what does that signify? I kept seeing it in my differential geometry class, but the professor never told us what it was.
>>8063378
for real
mRw^2 = 0.5kR^2
thus, R=(2m*w^2/k)
>>8063430
en.wikipedia.org/wiki/Time_derivative
>>8063451
Thank you friend.
>>8063450
Check dimensions: MRw^2 is a force while kR^2/2 is an energy.
>>8063414
You need a minimum radius r (unstretched spring or mass offset from center)
Mw^2R = k(R-r) -> R(k-Mw^2) = kr -> R = r/(1-Mw^2/k)
>>>/b/683646934
get headache from this stupidy
