Does the KVL equation in the image shown make sense?
dunno
result looks good
>>7977796
how do results look good?
the only way the results look good to me is if the voltage across the 8 ohm resister was 304.
>>7977819
>resister
what
>304
what
i(t)=i0*e^-(t*R/L)
t=0 --> i(t)=i0=2A
2A*8Ω=16V
>>7977859
i agree that the current is 2A so obvious i*r = 16.
conduct KVL around the loop with v1 = -160 and v2 = -144.
-160 + -144 + vR = 0
>>7977883
I'm guessing it would be -160 - (-144) + vR = 0?