Can anyone see what the pattern is here? Or at least how to go
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Can anyone see what the pattern is here? Or at least how to go about solving it?
f(x,y,z) = 2x + 4yz
>>7970438
How are we supposed to see a pattern of z when it's the same every time in your example?
2x + 8y
f(x,y,z)=z(x+4y)
Post another
>>7970438
There are at least infinitely many C-infinity functions that meet all of those constraints.
thanks guys
>>7970450
sorry im stupid
>it's an OP horribly tries to hide the fact he's asking us to do his homework episode
>>7970458
Here you go.
>>7970469
2x + 4yz again.
>>7970443
How did you come up with this? Does a non-brute force method exist?
>>7970491
-9xz -3y
Damn the second one is the trick :(
>>7970496
thanks it worked :)
>>7970526
Looking eq 1 and 3, we see the only difference is x changes by 1. This results in a change in f of 2. The same is true of eq 2 and 4.
So our first guess will be f(x,y,z) = g(x,y,z) + 2x.
g = f - 2x.
g = {0, 8, 0, 8}
So we have a new set:
g(0, 0, 2) = 0
g(0, 1, 2) = 8
g(1, 0, 2) = 0
g(1, 1, 2) = 8
We notice that if y is zero, then g is zero. Also, comparing eq 1 and 2 or eq 3 and 4 we see y changes by 1 and g changes by 8.
So we conclude that g(x,y,z) = 8y.
Since z is 2 in all cases, we can replace any appearance of 2 with z.
Thus our solutions thus far are:
f(x,y,z) = 2x + 8y
f(x,y,z) = 2x + 4yz
f(x,y,z) = 2x + 2yz^2
f(x,y,z) = 2x + yz^3
f(x,y,z) = xz + 8y
f(x,y,z) = xz + 4yz
f(x,y,z) = xz + 2yz^2
f(x,y,z) = xz + yz^3
This thread turned out surprisingly interesting, cheers lads!
So why did you pick the second solution?
>>7970438
f could just happen to map those points to those scalars and do something completely different everywhere else
you need more information about f
Why do people post funtions that depend on z if it's always set to 2?
2x+8y
is the simplest solution
[math]\left(\begin{matrix} 0 & 0 & 2 \\ 0 & 1 & 2 \\ 1 & 0 & 2 \end{matrix} \right)\cdotp a = \left(\begin{matrix}0\\8\\2\end{matrix}\right)[/math]
[eqn]a = \left(\begin{matrix}2\\8\\0\end{matrix}\right) \\f(x,y,z) = 2x+8y+0z[/eqn]
>>7970438
2x+8y+0z
>>7972576
baby's first LA
>>7970438
Can you not just do High School simultaneous?
>>7970438
ac+4bc
