what function could do something like this? (pic related)
it exponentially increases when it gets close to R but after it gets too close, it exponentially decreases
Gaussian distributions.
>>7954177
I forgot to say, the exponential decrease as to be much more faster than the exponential increase, is there any way to trunk a gaussian distribution for this?
>>7954171
Gaussian distribution, maybe you could say Lorentzian, but certainly not a function you learned in high school.
>>7954171
reverse Milankovitch cycle
>>7954187
Sure. Just envelope it with some function that kicks in after R and make sure it keeps it continuous at R. It won't be a Gaussian distribution anymore and it'll be ugly since it's piecewise but it'll do what you want.
>>7954202
same poster, Rayleigh distribution is what you're looking for actually, that'd be better.
>>7954171
Attractiveness of breasts
>>7954216
OP didn't post a monotonically increasing function, though.
>>7954217
I'm guessing he meant with respect to size as size increases. In which case I'd agree. Huge boobs are not attractive at all.
>>7954209
is there any way to reverse it? It does exactly what I want but in the oposite way: it increases greatly that it decreases
>>7954229
Reflect it across the y-axis.
>>7954235
ah, this, obviously, thanks anon
fourier
f(x)
= -1+e^x for x in [0;R]
= -1+e^(R-(R-x)^2) for x in [R;+infinity]
>>7954171
asymmetric/skew normal distribution
>>7954171
[eqn] f(x)= \begin {cases} e^{x} & \text {if } ~ x < R \\ 0 & \text {if} ~ x \geq R \end {cases} [/eqn]
>>7954229
Am I the only one who had a good laugh at this post?
>>7954171
looks like the energy profile of some kind of exergonic reaction (i googled that word)
maybe chemists have some canonical form for this sort of thing
>>7954171
A piece-wise function with the discontinuity removed.
