If I have a bucket of 10 unique objects and I pick out 3 samples. How many total samples are there?
10x9x8 would give me 720 but then for each set there are 5 more possibilities of obtaining the same set I think. Do I just divide by 6 and get 120? Is that right?
What I'm really asking is what's the best/quickest way to go about solving this?
If you are looking for the total amount of unique sets with out regard for order, then yes, you divide by 6. This is known as a combination, instead of a permutation, which depends on order as well.
https://en.m.wikipedia.org/wiki/Combination
10 choose 3 = [math]10 \choose 3[/math] = 120
Look up " probability and combinatorics"
https://www.mathsisfun.com/combinatorics/combinations-permutations.html
Best
>>7952785
[eqn]\frac{10!}{(10! - 3!)3!} = 120[/eqn] FTFY
>>7952772
>no traps
>no triceps
fucking curlbro assassin
>>7952831
except it's (10-3)! and not (10!-3!)
so actually you didn't fix anything, you just ruined something
>>7952852
Still outputted 120 m9
