[Boards: 3 / a / aco / adv / an / asp / b / biz / c / cgl / ck / cm / co / d / diy / e / fa / fit / g / gd / gif / h / hc / his / hm / hr / i / ic / int / jp / k / lgbt / lit / m / mlp / mu / n / news / o / out / p / po / pol / qa / r / r9k / s / s4s / sci / soc / sp / t / tg / toy / trash / trv / tv / u / v / vg / vp / vr / w / wg / wsg / wsr / x / y ] [Home]
4chanarchives logo
Knowledge test: What is the area of the circle that is not covered
Images are sometimes not shown due to bandwidth/network limitations. Refreshing the page usually helps.

You are currently reading a thread in /sci/ - Science & Math

Thread replies: 22
Thread images: 5
File: circletriangle.png (9 KB, 475x419) Image search: [Google]
circletriangle.png
9 KB, 475x419
Knowledge test:
What is the area of the circle that is not covered by the triangle?
>>
>>7923269
Nice try in getting us to do your homework.
>>
15.42 cm^2
>>
>>7923269
15.35 units
>>
>>7923269
2.5*rad(3)*x=2.5*2.5
X=2.5/rad(3)
Diameter = 2.5*rad(3)+2.5/rad(3)
Area of circle minus triangle = (diameter/2)^2*pi-2.5^2*rad(3)
=15.4
>>
File: 1457664581215.png (18 KB, 475x419) Image search: [Google]
1457664581215.png
18 KB, 475x419
>>7923269
>anons cannot into geometry

(75sqrt(3)-100pi)/12

be precise, faggots.
>>
File: Screenshot_2016-03-10-19-20-14.png (435 KB, 1080x1920) Image search: [Google]
Screenshot_2016-03-10-19-20-14.png
435 KB, 1080x1920
>>7923320
Interesting, I used this proof to find the radius
>>
File: frampt.jpg (135 KB, 500x486) Image search: [Google]
frampt.jpg
135 KB, 500x486
>>7923320
>the area is negative
AAHAHAHAHAH oh wow, please be bait
>>
Try the homework board
>>>/hm/
>>
1 equilateral triangle > 3 obtuse triangles
Find by the sen theorem one of those isosceles sides.
Isosceles side=circunference radius
Find the height of the triangle by the pythagoras theorem
Pi*r^2-2,5*height

Why do you get so mad?
>>
[eqn]\frac{25\pi}3-\frac{25\sqrt{3}}4[/eqn]
>>
easy
r = 2.5/cos(30)
area of circle = pi*r*r
area of triangle = (1/2)*5*5*sin(60)
now calculate the difference
>>
[math]\frac{25}{12}(4\pi-3\sqrt{3})[/math]
>>
[math] \frac {25} {12} (4\pi - 3 \sqrt{3} ) [/math]

You have to add spaces to your math every 10 characters or so. An anon said it has to do with the mobile version of the site not understanding the equation if there's too many characters in a single line.
>>
>>7923330
Just curious, how do you know that angle ABC is right?
>>
>>7924174
thales
>>
>>7923269
>Knowledge

You mean we should already know the answer and not need to calculate it? Because I don't already have the knowledge of that value. I could probably calculate it for you, but I'm not doing your homework for you.
>>
File: equi.png (6 KB, 264x229) Image search: [Google]
equi.png
6 KB, 264x229
ITT: people who don't know shit about triangles

you should at least know that the fucking radius of circumscription is 2/3 the height. Jesus
>>
-1/12
>>
We may already have answered your question. But in the future, would you please post your homework in >>>/hm/ , which is dedicated to just that?
>>
>>7925030
upvote
>>
>>7923898
Fug, that's what I was doing wrong. Thanks friendo.
Thread replies: 22
Thread images: 5

banner
banner
[Boards: 3 / a / aco / adv / an / asp / b / biz / c / cgl / ck / cm / co / d / diy / e / fa / fit / g / gd / gif / h / hc / his / hm / hr / i / ic / int / jp / k / lgbt / lit / m / mlp / mu / n / news / o / out / p / po / pol / qa / r / r9k / s / s4s / sci / soc / sp / t / tg / toy / trash / trv / tv / u / v / vg / vp / vr / w / wg / wsg / wsr / x / y] [Home]

All trademarks and copyrights on this page are owned by their respective parties. Images uploaded are the responsibility of the Poster. Comments are owned by the Poster.
If a post contains personal/copyrighted/illegal content you can contact me at [email protected] with that post and thread number and it will be removed as soon as possible.
DMCA Content Takedown via dmca.com
All images are hosted on imgur.com, send takedown notices to them.
This is a 4chan archive - all of the content originated from them. If you need IP information for a Poster - you need to contact them. This website shows only archived content.