Did I break math?

>>7791713
that epic feel when you draw a line i units long

>>7791713
You cannot of a length of "i". Using the isomorphism [math] \mathbb{C} \cong {\mathbb{R}^2} [/math] you could roughly equate [math]i[/math] with the 2-tuple [math]\left( {\begin{array}{*{20}{c}}
0 \\
1
\end{array}} \right)[/math]. This is not a quantity that you can define as a length. The best you could do is a define as a length as the modulus of i, which is just 1.

>>7791728
>>7791736
phew thanks

>>7791713
length is defined as a real number, complex length does not exist. therefor your triangle cannot exist.

>>7791713
no you're fucking retarded
let's say
a+bi=z
and
abs(z)=sqrt(a^2+b^2)
so
i==1*i==b*i for b=1 ; a=1
then
abs(z)=sqrt(1+1) => abs(z)=sqrt(2)

grab a book and stop asking retarded questions

what's next? drooling over e^(pi*i)=-1? for fuck's sake