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Simplifications


Thread replies: 32
Thread images: 7

File: image.jpg (1MB, 3264x2448px) Image search: [Google] [Yandex] [Bing]
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Simple question if this could be reduced any further and if so what exactly?
>>
2/20 = 1/10

u retarded m8?
>>
Underage b&d.

7/(2sqrt35)
>>
>>7733404
Quality thread.
>>
>>7733417
>>
>>7733404
Just in case it wasn't clear and you were serious op, the answer is:

(sqrt(35)) / (10)
>>
>>7733404
here, m8
[eqn]\frac{2\sqrt{35}}{20}=\frac{2}{2}\frac{\sqrt{5\cdot 7}}{10}=\frac{\sqrt{5}\sqrt{7}}{2\cdot 5}=\frac{1}{2}\sqrt{\frac{7}{5}} [/eqn]
>>
>>7733455
woop
[math][eqn]\frac{2\sqrt{35}}{20}=\frac{2}{2}\frac{\sqrt{5\cdot 7}}{10}=\frac{\sqrt{5}\sqrt{7}}{2\cdot 5}=\frac{1}{2}\sqrt{\frac{7}{5}} [/eqn][/math]
>>
>>7733452
>>7733437
Actually if I am right. >>7733417 is a more simple way of expressing it.
>>
>>7733458
What am I doing wrong?
[math]\frac{2\sqrt{35}}{20}=\frac{2}{2}\frac{\sqrt{5\cdot 7}}{10}=\frac{\sqrt{5}\sqrt{7}}{2\cdot 5}=\frac{1}{2}\sqrt{\frac{7}{5}}[/math]
>>
>>7733492
I'm just gonna play around a bit.

[eqn] \frac{2\sqrt{35}}{20} [/eqn]
>>
>>7733515

[eqn] \frac{2\sqrt{35}}{20}=\frac{2}{2}\frac{\sqrt{5\cdot 7}}{10} [/eqn]
>>
>>7733518

[eqn] \frac{2\sqrt{35}}{20} [/eqn]
[eqn] =\frac{2}{2} \frac{\sqrt{5\cdot 7}}{10} [/eqn]
>>
>>7733525
[eqn]\frac{2\sqrt{35}}{20}=
\frac{2}{2}\frac{\sqrt{5\cdot 7}}{10}=
\frac{\sqrt{5}\sqrt{7}}{2\cdot 5}=
\frac{1}{2}\sqrt{\frac{7}{5}} [/eqn]
>>
>>7733549
how did you get 1/2 from sqrt.5/2?
>>
>>7733728

The 1/2 is already there. See that 2 on the bottom?
>>
>>7733728
/sci/ - retarded highscoolers
>>
File: Untitled.png (6KB, 705x231px) Image search: [Google] [Yandex] [Bing]
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>>7733734
this is what i'm seeing. i apologize for my stupidity in advance.
>>
>>7733728
[eqn]\frac{\sqrt{5}\sqrt{7}}{2\cdot 5} = \frac{\sqrt{7}}{2}\frac{\sqrt{5}}{5}=
\frac{\sqrt{7}}{2}
\frac{\sqrt{5}}{\sqrt{5}\cdot \sqrt{5}}=
\frac{1}{2}
\sqrt{\frac{7}{5}}\frac{\sqrt{5}}{\sqrt{5}}[/eqn]
>>
>>7733746
ugh, how annyoing
[eqn]
\frac{\sqrt{5}\sqrt{7}}{2\cdot 5} =
\frac{\sqrt{7}}{2}\frac{\sqrt{5}}{5}=
\frac{\sqrt{7}}{2}
\frac{\sqrt{5}}{\sqrt{5}\cdot \sqrt{5}}=
\frac{1}{2}
\sqrt{\frac{7}{5}}\frac{\sqrt{5}}{\sqrt{5}}
[/eqn]
>>
>>7733743
Isn't it (1/2)(sqrt(7/5))?
>>
File: fucknig.png (116KB, 1388x978px) Image search: [Google] [Yandex] [Bing]
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116KB, 1388x978px
>>
>>7733755
how? wouldn't the 5 still stay on the numerator? you only simplified the denomator if it's 1/2.
>>
File: man.png (16KB, 1592x217px) Image search: [Google] [Yandex] [Bing]
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>>7733748
I'll just use KLatex.
>>
/sci/

Where people literally can't simplify fractions.
>>
>>7733766
like you could do any better i bet you can't even do triple fractions.
>>
>>7733762

Holy shit. sqrt(5)/5 = 1/sqrt(5). Now stfu.
>>
>>7733764
oooooooooooooh that makes sense. thanks for the clarification.
>>
>>7733764
as thanks take this serenade

http://vocaroo.com/i/s0negHZCGsT4
>>
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>>7733762
>>
>>7733757
It works with preview input field, m8.
But not in the message box one, something about linebreaks screwing with the code.
>>
(2sqrt(35))/20= sqrt(35)/10= sqrt(35/100)=sqrt(7/20)
Thread replies: 32
Thread images: 7
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