Hey /sci/ i was helping my little brother when he asked me to solve a question that i couldnt solve. Wondering how you can solve it. Question 20 in pic related
>sideways pic
>comic sans
this is clearly just bait. kill yourself. sage.
>>7673307
Heres a rotated pic. And what his retarded teacher uses as a font isnt my problem
use the pythagorean identities
>>7673311
Im know i have to use them but how? Can you solve this or atleast explain how you do it?
>>7673313
use yooug goddamned brain, faggot. sage again.
>>7673319
Nice bait
>>7673313
no, if you can't figure that out, you shouldn't get credit on the assignment.
>>7673322
Its not my work nor is it an assignment. Its my younger brother's math homework. What is wrong with you people?
I want a thanks for my shitty looking work.
>>7673324
Mathematics is learned through the hand.
>>7673330
Thank you very much kind sir but i asked for question 20. Thanks for the effort!
>>7673332
10 different attempts at a question with no avail is just wasting time
>>7673333
Its the exact same process with different identities
Download the symbolab app, its 5 dollars and will help you through most problems up to calc 2
LHS
Change the 1 into sec^2(x) - tan^2(x)
then you get -tan^2(x)
then multiply the numerator and denominator by (cot^2(x) - 1)
you're done
just study your identities please.
>>7673365
Finding the LHS that is.
>>7673365
Ok thanks. This one alone was pretty hard
This is not a place for Ask because they easily can fool you
Here ya go
>>7673387
Yes this makes total sense. Thanks
>>7673335
>10 different attempts at a question with no avail is just wasting time
On the contrary. You learned more doing that than being spoonfed the answer by some fag trying to look smart who doesn't realize this isn't a homework help board.
>>7673310
18) just foil, then apply sin^2(x)+cos^2(x) = 1
20) just multiply by 1. 1 = tan^2(x)/tan^2(x).
1*(tan^2(x) - 1)/(cot^2(x) - 1) = [(tan^2(x))/(tan^2(x))]*(tan^2(x) - 1)/(cot^2(x) - 1)
= tan^2(x)*(tan^2(x) - 1)/[tan^2(x)*(cot^2(x)-1)]
=tan^2(x)*(tan^2(x) - 1)/(1-tan^2(x)) = -tan^2(x) = -(sec^2(x) - 1) = 1-sec^2(x)
22) just multiply the numerator and denominator by cos^2(z), then apply cos^2(z)+sin^2(z) = 1 to the denominator.
>>7673555
Just bored at work, decided i would try them.
