Good luck Robits
3 dy/dx
>>27325230
I think it spells out that OP is a faggot.
>>27325230
>2s that look like backwards 6s
>square brackets
>?
i cna't solve shit
>>27325230
That's pretty easy
deriving 3y with respect to x will introduce dy/dx, and with the product rule ([0][[y] + [3][dy/dx]) you will get 3*dy/dx, and the derivative of the constant 1 will be 0 so answer is 3 dy/dx
2/2x(3y-1) = ?
simplify 2/2x to 1/x
1/x * 3y = 3y/x
1/x * -1 = -1/x
3y/x - 1/x
3y-1/x
y = 1/3
okay here's the next question
>>27325382
Scissors. Next!
>>27325374
nigger...that's d/dx, not 2/2x
kinda hard to tell from OP's SHITTY handwriting though
>>27325230
muh derivitives
Math is fun!
Now without OP's paintwriting
I used to be pretty good at this. Wish I could still do it.
>>27325416
-2(rcostheta)^-3*dx/dr -2(rsintheta)^-3*dy/dr ??
>>27325416
-2/r^3
>>27325230
Yo, why don't we integrate it up in this bitch
>>27325504
-4cos(1) +4cos(0) =
4-4cos(1)
>>27325230
0
Original1234
>>27325533
ding ding ding das right!
Ammar is that you?
Stop getting people to do your calc homework and study Statics!
>>27325230
the answer is 0
>>27325489
Hint:
Sin^2& + cos^2& = 1my phone doesn't have fancy characters
It's not hard :^).
Integration is boring anyway.
>>27325230
Zeeeeero.sk
>>27325692
Where do I use the power rule?
>>27325504
>sin(dx) or sin(d) * x
>not integrating with respect to anything
nigger what the fuck is this
>>27325591
So first I subbed those values in, expanded them before deriving since you gave the hint of the identity so cos^2 + sin^2 = 1, and then used the quotient rule to derive this. In the end, I got:
[4r - 2rsintheta + costheta + 2rcostheta + sintheta]/[2r^2 + 2rcostheta + 2rsintheta + 1]^2
>>27325756
sorry I forgot the x >.< my calculus is dusty
>>27325692
Man, I sucked at the theory of linear algebra.
I can solve problems with it, but proofs are my weakness.
>>27325745
Nowhere. senpai
Wrong branch of maths.
>>27325775
One tip.
There exists a linear map to every matrix and to every matrix a linear map.
>>27325692
>linear algebra
nigger get the FUCK out of here!
>>27325773
Lets get some cylindrical integration up in dis bish
>>27325834
Only because you cant do REAL maths :^).
>>27325692
If rank(A)=n then you can form every standard basis vector through linear combinations of the columns of A. Let these linear combinations be the columns of B, then B is inverse of A.
If A is invertible then the standard basis vectors are in the image of A thus dimension of image of A is n thus dimension of col space is n and so rank(A)=n.
>>27325840
tf is that shit senpai? Didn't learn that yet...
>>27325859
>Auto
seems right, another idea is:
There exists a linear map so that: n=Rank(A)=Rank(f) so its bijective therefore exists a f^-1 and a matrix B which corresponds to it and is the inverse (because f^-1 o f =id).
The other direction is nearly the same but backwards.
>3 dimensional derivation
I'm scared
You know how to count right?
Another one.
You like linear algebra right anon?
Is it 1?
Don't mute me I'm doing math
>>27325416
(-2)*[r^(-3)]
>>27326061
Man I fucking hate linear algebra, I almost failed that shit last semester.
>>27325230
0
>>27325416
0
>>27325504
The x is missing
You're one cheeky cunt.
>>27326126
Its fun. Unlike analysis.
The proofs in LA, at least for me, seemed always a lot clearer and easier to understand then the ones in Analysis.
>>27326081
This answer was meant for >>27326061
>>27326174
My course is called engineering analysis but it's actually a linear algebra couse
pretty crazy amirite?
>1st year math
git gud
>>27326177
Sorry anon the answer is wrong :^(.
>>27326174
>analysis
>not fun
Anal is pure fun nigga.
>>27326213
:^)
>>27326181
That seems pretty weird.
>>27325230
Look I only did high school maths and the only basic maths level at that. What you wrote is gibberish to me.
>>27326259
Where do you study math-anon?
>>27326278
Its called Technomathematics.
Its Math and some Engineering/Compsci.
>>27326061
>tfw haven't done any math in a year
I'm rusty but I got det(An)=(-1)^(n-1)n.
Reminded me of problem I did on putnam.
Pic related.
>>27326313
Oh read that wrong, northern Germany.
>>27326313
Sounds cool. I'm in Bionics Engineering. Fuckload of math, physics, chemistry, biology and programming. Keep up the good work.
>>27326339
Thanks anon, same to you. Bionics engineering also sounds very cool.
>>27325230
I'm gonna bang you tonight bby
>>27325230
0
>>27325382
girls can't love girls!
>>27325416
(-2/r^3) * (1/((sin(theta)*cos(theta))^2) = (-2/r^3)
>>27325504
uhh, what?
assuming there's an x after that sin, 4 * (1 + cos(1))
These are all the problems I can solve without paper.
>>27326314
det(A) is always 1.
>>27326314
Your solution is right. Good work anon.
I know you can solve this /r9k/!
>>27326509
Are you referring to my solution or the pic?
Either way just look at 2x2 case.
>>27326525
le -1/12 :^)
>>27326525
SUM n=1 infinite (n) = infinite
You don't get to bring memes.
You like graphs right anon?
>>27326525
Just let the -1/12 meme die
>>27326543
forgot the 1/.
det(A)= prod(2<=i<=n)((1/n)-(1/(n-1)))?
so for 3*3 its
(1/3-1/2)*(1/2-1)
I like that there are a lot of smart robots here.
Keep it up, lads
>>27325230
just another simple integral for you'll cowards
>>27326726
Looks right to me, you can write it a bit simpler as
(-1)^(n-1)/(n!(n-1)!)
>>27326727
>smart
anyone who can solve a problem I can solve is not smart
>>27326860
Have you solved every problem itt?
Let's do some practical linear algebra.
>>27325230
Zero. That's a partial derivative so you just treat the 3y as if it were a constant.
>>27327015
Why wouldn't it be an implicit derivative anon? If you wanted to derive y with respect to x, you could represent that as dy/dx, so your answer would end up becoming 3*dy/dx.
>>27327041
The weird curvy d looking thing means partial derivative.
>tfw can't solve any of these
>>27327057
Oh shit, is this differential equations? If so, then that would explain it. I'm taking that next year.
>>27327004
91/sqrt(246)?
>>27327078
it's just multivariate calc.
>>27327089
Yeah, around there.
I got 5.81378, but that's probably just rounding issues.
Are you up to the challenge, anon?
>>27327188
McLaurin series for e^x is sum(x^n)/n!
Sub x for -x^2 for sum-x^(2n)/n!
Integrate for sum-x^(2n+1)/(2n+1)n!
Evaluate from -inf to inf
Fucking 0 you retards. The only variable is y, and you have to derive by X.
>>27325416
Let @=theta
since x=rcos(@)
and y=rsin(@)
then x^2 = r^2cos^2(@) and y^2=r^2sin^2(@)
therefore: 1/(r^2cos^2(@) + r^2sin(@))
factor out r^2 so that the equations becomes (1/r^2)*(1/(cos^2(@) + sin^2(@)))
cos^2(@) + sin^2(@) = 1 (trigonometric identities)
Therefore the equations becomes (1/r^2)*(1/1) = (1/r^2) =r^-2
now since we're DERIVING THE FUNCTION (not fucking multiplying by 2/2r you illiterate fucks):
r^-2 becomes -2*r^-3 which can be written as -2/r^3
I believe in you anon-kun.
>>27327188
when evaluating:
e^-(-inf)^2 =e^(inf)^2=infinity and e^-(inf)^2 = 0
so from infinity to negative infinity,
0-infinity = -infinity
>>27327231
You will have divergence when evaluating infinity^n
>>27327312
lol
>>27327286
I think it's 13.5, but it's been a long time since I did any math.
>>27327447
Think that's right.
>>27327188
Sqrt(pi)
