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Help me with #16 pls ok ty
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Help me with #16 pls ok ty
>>
>>25080148
It's true and you can test this yourself.

a/5 equals b/3

therefore b/3 equals a/5

a/5 equals a/5

Does 5/a therefore equal 5/a?

Yes, it does.
>>
>>25080181
Ok ty friend!
>>
A/5 = b/3
Just fill other numbers I'm
15/5=9/3
5/15=3/9
5/15 is not 9/3
>>
>>25080181
That makes no sense.

>>25080266
This is how you'd disprove with an example.
>>
>>25080266
>numbers

Sure thing lad
>>
>>25080148
multiply left and right sides by 25/a^2
25/a^2 *a/5=b/3*25/a^2 => 5/a=(25b)/(3a^2)
pretty easy desu senpai
>>
>>25080148
The error is that he's just invereted the left fraction for no reason.

The assumption that y/x = x/y does not hold when y=/=x.
>>
>>25080148
As someone from /sci/ I almost pulled my hair out
a/5 = b/3
x/y = 1/(y/x)
therefore: 5/a != b/3

What happened to the "robots are smart" meme?
>>
>>25080148
No error in #16. A/B = 5/3 in both equations.
>>
>>25080353
we got invaded by people looking for a meme fix
>>
>>25080366
Wait the second equation is a*b = 5/3.
>>
>>25080353
>someone from /sci/
UH OH LADS HE BROWSES A SCIENCE BASED VIETNAMESE CARTOON BOARD HE CAN DO 5TH GRADE MATH
>>
>>25080148
The "error made in the reasoning" is that they assumed that the reciprocal does not change the value.


a/5 = b/3 => a = (5/3)b (from eqn 1)
ab = 15 (from eqn 2)
therefore
(5/3)b*b = 15
(5/3)b^2 = 15
=> b = +-3
so from ab=15, a = 5

So this is true for only b = 3, so it doesn't work for all possible values.
>>
>>25080349
Well I made a retarded response anyways since I didn't even correct "I'm" to "in"
>>
>>25080353
It's an underage middleschooler. Please mate.
>>
-5, not 5
>>
A= 5 b=3

What's the issue, again?
>>
>>25080148
Because a/5 would have to equal 5/a. What the fuck kind of bullshit math is this?
>>
>>25080352
It looks like the teacher added a "multiplied by x" to the right of the equation.
Thread replies: 20
Thread images: 1

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