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can any of you robots solve this. I bet you can't
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You are currently reading a thread in /r9k/ - ROBOT9001

Thread replies: 16
Thread images: 4
can any of you robots solve this. I bet you can't
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>>24115019

Do your own homework you stupid faggot.
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>>24115019
if dubs, 0 == -5
new mathematical discovery
let it be known throughout the land
>>
>>24115019
i don't remember the distance formula, but finding the values is super easy in this case.
>>
5/(square root sign)2

it's around 3.5
>>
>>24115076

Off by one. Just like OP's answer will likely be since he's retarded.
>>
>>24115019
First, you take the double integral of f(x,y)dxdy and then you kill yourself.
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>>24115019
5 you dumbass
>>
poo butt ass?
>>
>>24115019
Somewhere between 5 and infinity depending where on the lines you're measuring from.
>>
l:Ax+By+C=0

l1: -x+y+5=0 A=-1 B=1 C=5
l2: -x+y=0 A=-1 B=1 C=0

d= 0-5/square root of (-(1)^2 + (-1)^2)
d= -5/square root of 2
d= -5 square root of 2/2
>>
>>24115864
* d= 0-5/square root of ((-1)^2+(-1)^2)
My bad
>>
>>24115019
Hell no! Of course I can't.
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>>24115019
Solving it geometrically:
Think of a line that is perpendicular to your two parallel ones, e.g. y=-x and calculate the intersection of that line with the ones given in the exercise. The distance of those two points is the distance of the lines.

Solving it arithmetically:
Interpret the lines as a system of equations as >>24115864 did it, just don't be stupid and write a negative distance as your answer.

Just solve it:
Go to wolframalpha.com and enter "distance between y-x=0 and y=x-5"
>>
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It's really not that hard
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>>24116337
>>24115864
Fuck I actually did not think straight when I did it. Must be something wrong with me.
Sorry dude.
Thread replies: 16
Thread images: 4

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