x = bprint x == a or bIf you execute this code on python, the ouput is b instead

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>2013+3
>still using Python 2
to answer your question, the second statement is basically

print <expresssion>

, where 'expression' in this case is

x == "a" or "b"

. The value of that expression itself is the value of the first operand that is true, which is "b".

order of operations.

"==" is before "or"

So the 2nd line is equal to:

print (x == "a") or "b"

First do the parens

print (false) or "b"

"or" returns the second thing if the first one is false, so

print "b"

>>54961154

instead of shitting all over python 2.7.x be happy you don't have to maintain legacy code

Works just like the ternary operator from other languages

0 ? 0 : "b"

>>54961154
The thing is that I don't get why if

x = "a"

print x == "a" or "b"

outputs True instead of "a" which is the value of the first operand that is true. To me, it should output "a" if x = "a", "b" if x = "b" and False if x is anything else. I still don't get it?

I think im autist /g/

>>54961171
I would go further to define it like so:

print(((x == "a") or "b"))

because OP is an retard.

>>54961345
Look at this answer: >>54961171

Do these substitutions again.

print (x == "a") or "b"

print (True) or "b"

print True

If the first expression is not False, "or" will return that expression.
In this case,

True

>>54961345
I think you want

print x == "a" or x == "b"

or something to that effect. Or if python supports something like this:

print x in ["a", "b"]

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OP here. I fixed the code to work like I wanted to:

x = "b"
print x == "a" or x == "b"

Thx everyone. /thread

>>54961345
>I think im autist /g/
You're not. That code actually uses a shorthand that's common in many languages, which is that non-boolean (i.e. non True/False) values are treated as boolean in certain cases. True is obviously true and False is obviously false but other values like 42, "hello", and [1,2,3] can also be treated as true or false.
The value of the first operand in

x == "a" or "b"

is not x but everything preceding 'or', because that expression is equivalent to

<expr1> or <expr2>

. In this case, <expr1> is

x == "a"

, and the value of this is clearly True. However, in the earlier example, "b" is treated as True but its *value* is actually itself.
Confusing, I know.

>>54961345
It is equivalent to this
(I'm simplifying by using False instead of x == "a" because it resolves to False obviously)

print(False if False else "b")

>>54961439

OP here. Hey, looks much more clear now.
Thanks.