>>679257422
(x-1)^0.5 + 7 = 2
(x-1)^0.5 = -5
square root is defined to always be >= 0 so no solution exists

>>679257422

Sqrt(x-1) + 7 = 2

Sqrt(x-1) = -5

x-1 = 25

x = 26

However, this solution does not work when checking.

sqrt(26 - 1) + 7 = 2

sqrt(25) + 7 = 2

5 + 7 = 2

12 =/= 2

Therefore there is no solution

26 no problem fagoots

>>679257422
x = 26
-7 on both sides square both sides to remove square root, plus one, simple math

videogames

26? Fuck if i know

>>679257687
many thanks, anon ... i was struggling to come up with an answer because i couldn't fathom any square root that would equal a negative number (not op)

82..

>>679257422

Twenty-six

>>679257907
Sqrt(25)=5 and -5

>>679257907

This is correct. Squaring does not always preserve equality.

Gotta check dat answer; 26 doesn't work.

>>679257907
You were close. Remember that the sqrt gives positive and negative 5 as the answers. Negative 5 is the true solution.

all you fags saying 26 are just complete faggots go back to middle school

>>679258386

Mean't to say square root does not always preserve equality

>>679257422
x=-2

>>679258313
incorrect.

the sqrt function/operation is always defined to be positive. you can test this yourself by graphing it on a graphing calculator.

However, it is true that the solution set for x^2 = 25 is 5 and -5

>>679257422
No solution for x in IR

>>679257915
>>679257923
>>679258004
>>679258158
sqrt(26-1)+7 =/= 2
Fuckers

>>679258394

>>679258593

>>679257687
umm no. -1^.5 = j
where j is imaginary

>>679258386
You have to use a plus/minus, there are two answers. Not one.

now let's try a geography question, and don't look at a map:

what continent is due south of greenland?

>>679258750
>-1^.5 = j
what the fuck?

it's sqrt(-1) = i
i is imaginary, it's the first fucking letter. J? what the fuck?

It's 26. Square root as inverse of square has two solutions, positive and negative. Usually square root symbol means positive, but if you're hinging on that then fuck this question.

>>679258814

S.America

>>679258952
>fuck this question
non-mathing autismo detected

>>679258814
Every fucking continent

>>679258904
j is used everywhere in engineering. i isnt used

>>679258806
There is only one solution because the original equation's highest power is 1.

26i
i represents (sqrt) -1 because a typical square root can never equal a negative, it is an imaginary number
>>679257907
and for anyone who said no solution

>>679259025
very good. this surprised me when i realized it

fuck you and your math bitch

>>679258593
Always? It's been a while since I took math, but I don't remember that rule.

>>679257422
x - 1 = 25
x = 26

>>679259273
said the autist

26

>>679259273
correction, Square root of X-1 = -25

x=26
Take the negative root when you sqrt 25

>>679257422
nigga im a math major the answer is x=24

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>>679259495
>nigga im a math major

>>679259205
It's not a rule, it's a property.

While very similar, if we were to include both positive and negative solutions for an equation of the form: sqrt(x) = c, then we would be violating the injectivity (or one-to-one -ness) of the sqrt function, thus making it not a function.

ie. including negatives will violate the vertical line test.

>>679259495
or 26 depending on the +/-

>>679257687
The square root of a negative number has both a real and imaginary portion. Go back to 10th grad fag.

Source: Theoretical computer science grad student.

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>>679259495
>X=24

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>>679257422
Always check answers.

>>679259495

Maybe Art history is more your speed

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>>679257422

>>679259495
>nigga
>math major

>>679259643
check
>>679259122

x = +/- 25 + 1

>>679259122
ya the sqrt(26i-1)=/= -5

the original case has no solution simply because you cant sub the answer back in

>>679259745
-26,24

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>niggers calling them "imaginary" numbers

>>679259814
Can't sub the answer back in? how so? with the use of imaginary numbers there never is 'technically' an answer, if that's what you mean

>>679259081
No, it's square root on one side, or squared on the other. The highest order is two.

>>679259956
fuck off jon, ill push your ass down a hill you fat cunt

>>679257422

Now I could be just a moron, but could someone enlighten me as to why this solution may be wrong:

SQRT (x-1) = 9

Square both sides, removes the sqrt symbol, giving x-1 = 81, Then add 1 to both sides giving x=82. Am I retarded?

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√(x-1)+7=2
√(x-1)=-5
square both sides
x-1=25
x=26

>>679260205

I am retarded. I just added a number I should subtract. TIME TO AN HERO

>>679260205
subtract 7 from 2, not add.

it makes -5, not 9

>>679260089

Incorrect. Again, including both positive and negative solutions violates injectivity

>>679260205
good idea. messed up 1st step. no idea why you thought to add the 7 and 2, while you should have subtracted because of opposite sides

>>679260205

But yeah, redid it and got 26. Squaring -5 is 25, add 1. Straightforward right?

>>679260362
What does the arrow mean in algebra again?

>>679260448
as x approaches infinity.

>>679260448
I think that's trying to depict a limit

>>679260315

Redid, got 26. Sleepy.

>>679260220
-5^2 is not just 25 its + or minus 25 b/c look it up

>>679260362

>limit of f(x) equals a function of x
>limit of f(x) equals a +/-

This is literally nonsensical. Not even an "I don't get it" nonsensical, but a "This isn't how limits work" nonsensical.

>>679257422
sqrt(x - 1) = -5
So, whatever is under the radical = 25i
25i = x - 1
x = 25i + 1

it doesn't have an imaginary solution either gay boys

the square root of a complex number with a nonzero real and imaginary parts is equal to a complex number with nonzero real and imaginary parts

>>679259071
>i isn't used in engineering
Go back to high school dude

https://www.wolframalpha.com/input/?i=sqrt(x-1)%2B7%3D2+solve+for+x

>>679260967
check 'em

sqrt((25i+1) - 1) + 7 = 2

sqrt(25i) + 7 = 2

doesn't check out, bruh

>>679257422
This has no answear, b/c you cannot have a negative after you square root the x, therefore any number after zero including zero would eventually be added to 7 making (something) + 7 =|= 2

>>679260345

I'm just dropping by to say that injectivity is not a requirement of a function.

>>679260967
square both sides, not sqrt(-5)

>>679261459
In order for a relation to be a function, it must be a bijection, aka injective and surjective.

injection is essentially the vertical line test: every f(x) must have at most one x.

>>679261145

not the same fag. j is used much more often in engineering. Enjoy your liberal arts degree

>>679261411
imaginary solutions nigga

>>679257422
i never passed algebra

>>679261659
CE major. Current is pretty important. Not to mention the fact that anyone majoring in engineering has to take plenty of math classes where i is used extensively.

x=26 but if you plug it back in it breaks because sqrt(25) can be 5 and -5 at the same time.

X=-25i+1

>>679261636
I thought this wasn't a function in the sense it wasn't defined as one. It's merely an equation.

>ITT: Faggots who never passed Algebra I

>>679258814
>>679259025
Interesting point to add:
The eastern-most point of mainland Greenland is due north of mainland Africa.

>>679262025
the square root is function

but I also brushed up on my set theory, and a function does not need to be injective. my bad there.

>>679261720

>>679261117

x = 2

>>679260220
Let's try that out

√(x-1)+7=2
x=26
√(26-1)+7=2
√25+7=2
5+7=2
12=2

You fucked up

>>679260722
no it's not.
-5 x -5 =25
You're thinking of the fact that sqrt(25) has two solutions. 5 and -5

>>679257422
x = 25(i ^ 4) + 1

>>679262287
If you plug in -5 for the square rot of 25, it works fine.

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>>679257422
uh...4?

>>679260064
no there is no solution that is valid
imaginary numbers are simply a method for representation but 1i=/=-1 which is what youre thinking
which is why i stated
sqrt(26i-1)=/= -5
because for the equation to be true you need y+7=2 which means sqrt(x-1)=-5 and youll never get that answer

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>>679257422
>Let's see who passed intro algebra.
Ok

>>679262292

>You're thinking of the fact that sqrt(25) has two solutions. 5 and -5

-5 isn't a solution

>>679262523
It's a solution to sqrt(25)

>>679262413
You can't just choose to use one value and not the other. It doesn't work for +5, so it's not a solution.

>>679261636

I think you mean that injection is the horizontal line test: one and only one y value for each x given that f(x)=y is a relatiom mapping Set X to Set Y. The vertical line test is that f(x) multiple x's mapped to the same y. Then surjection is that every y in Set Y is mapped to a corresponding x value in Set X by f(x).

I'm pretty sure a function can exist without being bijective. Otherwise, basic functions such as polynomials and hemispheres wouldn't be considered functions, as the former is not injective and the latter is neither injective nor surjective.

At least that's what I was taught in my math classes.

>>679257422
x = 25i

You dumb shit

Guys the question is very simply "does a square root always mean positive square root." its a question of rules / conventions in math, not of arithmetic

>>679263081
test it, you nigger. it doesn't work and youre being cucked by a nigger as we speak

>>679262959

>The vertical line test is that f(x) multiple y's mapped to the same x.

Fuck, I'm tired. Probably a bad time to talk math on 4chan.

>>679258497
This is a trip. Just when I thought I was cushty for algebra, I get wronged again.
I would have said right off the bat that x=26. So the upshot of this is that squaring when you have a sqrt on one side and a -ve integer on the other does not necessarily mean that the negative disappears? Or am I being stupid?

>>679262523
5 times 5 equals 25
-5 times -5 also equals 25
thus the square root of 25 can be both 5 and -5. in this case, it's -5, and x = 26

>>679258632
sqrt(26-1)=+or-5 tho
-5+7=2
?

>>679263379
It actually has no solution
>>679263475
You have to use both 5 and -5 or it doesn't work

X= (1 + 81i^4)

>>679262012

on the right track, the negative is redundant

x = 25i + 1

thus:

sqrt(x - 1) + 7 = 2
sqrt([25i + 1] -) + 7 = 2
sqrt(25i) + 7 = 2
-5 + 7 = 2
2 = 2

>>679263853

second line should be

sqrt([25i + 1] - 1) + 7 = 2

sorry!

>>679263613
>It actually has no solution
if you don't elaborate on that, your post means literally nothing

>You have to use both 5 and -5 or it doesn't work
actually, you don't. -5 is the only one that makes the equation true so it's the only one you need to use. x = 26

>>679263803
i^4=1

>>679257422
X=26

>>679262503
>>679263613
>>679263379
>>679263081

see

>>679263853
>>679264044

dubs gets it

>>679264044
sqrt(25i) =/= -5

sqrt(25i) = 5 * sqrt(i)

sqrt(i) is approx. 0.707106781 + 0.707106781 i

so that doesn't work, friend.

>>679264457
x = 26 is a valid solution

>>679264127
no REAL solution. -5 is only part of the solution for sqrt(25).

>>679264457
see
>>679264569
69 gets it

i^4 = (i^2)^2......
so would sqrt(i^4)=sqrt[(i^2)^2] = i^2

>>679264574
No it's not. There's no +/- sign in front of the sqrt.
5+7=/=2

>>679264658
it's the only part you need for x = 26 to be true

>>679264816
see
>>679263379

>>679257422
you dumb niggers
sqrt(x-1)+7=2
>minus 7 from both sides
sqrt(x-1)= -5
>square both sides
x-1=25
>add 1 to both sides
x=26

x = [26,-24]

there are two solutions

>>679265007
x can't be -24

>>679264569
what's the answer?

>>679258952
But in ALL mathematics it cannot happen, it is only measured in positives as a formality.

>>679260220
EXTRANEOUS SOLUTION
>thinks person is smart
>forgets that not all solutions are answers

>>679264993
actually this isnt 100% true. mah B
This solution (x=26) only exists when the function sqrt(x-1) is equal to -5. other than that no other solutions exist.

>>679259590
But isn't the vertical line test only necessary for functions? Since this is just an algebraic equation isn't it proper to account for the negative solutions as well?

This is coming from a high school AP Calc AB student so I'm no authority, just wondering. Looking into careers in mathematics.

The answer is the symbol that looks like a zero with a line through it, or not applicable.

Imaginary numbers, guise, pls.

sqrt(a)=k implies a=k^2 only for positive k

sqrt(x-1) = -5
x-1 = 25
x = 24

>>679257422
minus 7 both sides equals -5
square both sides equals x-1 = 25
add one equal 24
x= 24, done

>>679257422
Passed algebra but forgot this shit instantly, it's really fuckin retarded and useless to know in the age of computers anyway.

>>679261411
Shit is undefined

>>679266181
26* holy fuck lol

>>679266181
Nice addition skills.

>>679257422
the solution does not exist

>>679265902
or {}

>>679257422
26

>>679257687
>square root is defined to always be >= 0 so no solution exists
kill yourself

>>679265097
sqrt(x-1)+7 = 2
>minus 2
(sqrt(x-1)+5)^2
x - 1 + 25 = 0
>simplify then minus 24
x = -24

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>>679266586

>>679266389
Right, could get the thing in my head.

>>679257422
x = 26

X=26. The square root of 25 is either +5 or -5. Solution doesn't work for +5 but does for -5. Dumb niggers

>>679266586
No
(sqrt(x+1)+5)^s = (x+1)+10sqrt(x+1)+25

>>679257422
No solution. A square root can't equal a negative value.

>>679267919
Square roots can be negative. You are thinking of the square root of a negative number.

This thread is atrocious. This is only 200-level community college math, people.

>>679257422
-4 minus 1 is -5 and -5 plus 7 is positive 2. So x = 2.
i don't give a fuck just give me a prize.

>>679268413
Not everyone is a math geek, fagget.

>>679266892
This is right

>>679268413
This is literally highschool level algebra. You should learn in the 10th grade that all positive numbers have a positive and a negative square root.

>>679258394
>>679258806
Are you retarded?
1) Square roots only have both negative and positive answers if you introduce the square root into the equation
2) We are squaring something, not finding the square root of something, which ultimately negates the negative
3) if you plug in -5 for X, you get root -6 which is an imaginary number

>>679257907
Square rooting splits it in two though, this just means there is only 1 solution, some square roots give zero solutions and some give 2.

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>>679264574
k

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>>679270699
kek just came here to post this

>>679270699
What does (-5)^2 equal? 25 right? Same thing with (5)^2. That means the sqrt (25) can be both -5 and 5. Square roots of positive numbers have both positive and negative results. Stop being a tard

>>679270699
>>679270816
No solutions in real numbers. In complex/imaginary numbers there should be an answer, to lazy to solve it.

>>679269424
thats not true, square roots are defined as positive. You are confused with the equation
x^2 = a --> x = +-sqrt(a)

>>679257422
26. wtf this is easy

no one said x > 0, so you can use -5

>>679272439
Sauce? Cause I can pull up about 50 that say that square roots can be either positive or negative.

>>679257422

1+SQRT[5]*I or 1-SQRT[5]*I

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>>679272008
okay

>>679273085
you are right they are that's why quadric equations have two solutions

>>679273258
Put a negative in front of the sqrt function. When this shit is first taught you are to see it as +/- sqrt(25) = +/- 5. Wolfram assumes it is just a positive value and solves for it as that. Kind of like what a calculator would do if you punched in sqrt (25)

>>679257422
x² + i + 7 = 2
x² + i = -5
x² = -5 -i
x = sqrt (-5 - i)

Closest thing I could come up with would be a limit.
x = lim(y->inf) 25*e^(2π-1/y)+1

>>679274031
>square root of a complex polynomial
Nigga what are you doing?

Is this supposed to be mind boggling?
Good gracious, you guys are fucking stupid.

>>679273085
sorry i got confused with real functions, only one y per x, because it wouldnt be a function otherwise

Watching people struggle with basic algebra confirms the shit hole of a society we live in.

>>679257422
(X-1)^0.5+7=2
(X-1)^0.5=-5
X-1 = i5^0.5
X=i*(5^0.5)+1

>>679274502
Shit. I meant:
x = limit (y->inf.) 25*e^(i2π-i/y)+1

X=26
X-1=25
Sqrt(25)= - 5 (-5x-5=25)
-5+7=2

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>>679274920
>limits for a basic algebra problem

>>679257422
srt (x-1) + 7 = 2

srt (x-1) = -5

srt (x-1)^2 = (-5)^2

X - 1 = 25

X = 26

Suck it.

>>679275256
Bitch. The only basic thing about this problem is your sorry ass.

>>679275256
That's what happens when you start working with i, bitches.

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26

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>>679264457
thats literally not how i works

>>679275421
A square root of an expression cannot be negative in the reals. If X=26 then 5+7 = 2

Suck it

>>679259071

>study engineering

>still use i


Who teaches u math anon?

>>679264457
ill further elaborate
taking sqrt of a negative number gives you i
squaring i gives you a negative number and as such
sqrt(-25)=sqrt(25)i=5i
i^2=sqrt(-1)*sqrt(-1)=-1 when referencing it through exponents of (-1^1/2)*(-1^1/2) which adds exponents giving -1
so how in the fuck does sqrt(i) give you a negative value? its -1^0.25 which =/=-1
it gives you sin45+sin45i

>>679274520
>square root of a complex polynomial
https://www.google.fr/#q=square+root+of+a+complex+polynomial

>>679275822
electrical engineering uses imaginary numbers extensively
who the fuck teaches you anything?

>>679275795
OP didn't state that x>0, and all positive square roots have both a positive and negative value. 5+7 =/=2 but -5 +7 =2
Suck it

>>679257687
There's no rule against squaring a negative number, which is the opposite operation to a square root. Obligatory "you're a fucking retard"

>>679276103
positive square roots only apply when you are making the square root, it was already given and thus is only the positive half

i dont see a +/- sign anywhere

>>679259071
This. Electrical engineer reporting in, we use the letter j for sqrt(-1), since i is usually used for current. Most of the engineering fields also adopt this notation due to the extensive reach of ee in other fields.

Impossible solution. what has to be added by 7 to get 2 is -5. It is impossible to take square root and get a negative number

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>>679257422
Tfw everyone who got the right answer gets called a retard

>>679276525
>It is impossible to take square root and get a negative number
That's true anon, but you can get complex numbers while taking the square root, and that's what you have to use here

>>679257422
Sqrt(x-1) + 7 = 2 [Sqr both sides]
x - 1 + 7^2 = 2^2
x - 1 + 49 = 4 [+ 1 - 49 both sides]
x = -44
----------

>>679257422
No solution. Next question

>>679276525
100% false. You can get both positive and negative values from square roots.
What people are basically saying is that (-)^2 = (+) but that sqrt (+) =/= (-) despite both of these things being the exact same shit.

>>679276742
complex numbers dont just make solutions magically work
you get a complex number from sqrt(-1) that still doesnt give you a negative solution from a sqrt
and the sqrt of the sqrt of -1 still isnt a negative number

>>679257422
x-1+7 = x+6

2 = the square root of 4, so anything under that square root must equal out to 4.

x+6 has to add up to 4, so x has to equal -4.

-4 -1 +7 = 4

so x has to be -4, right?

>>679276868
Can't do that dude. You would get
(Sqrt(x-1)+7)² =2²

>>679263853
sqrt(25i) is not -5 anon, you're getting confused there.
sqrt(25i) = sqrt(25)*sqrt(i) = 5*sqrt(i).
Now sqrt(i) = 0.707 + 0.707i, so what you wrote doesn't work out

26.
√(x - 1) + 7 = 2
√(x - 1) = -5
x - 1 = 25
x = 26
But anon is right about not continuing after -5 bc a root cannot be negative.

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>>679258750
>j
Dear Engineering,
Get the fuck out of here, faggots.
Love,
Science

>>679277949
Anon. You only do that if the interior of a root is negative. Not what it equals.

http://www.mathplanet.com/education/algebra-1/exploring-real-numbers/square-roots
"All positive real numbers have two square roots, one positive and one negative."
Therefore -5 works as an answer for sqrt (25).
/thread

>>679278137
>Anon. You only do that if the interior of a root is negative. Not what it equals.
No idea what you're saying, so I'll just say it again: i^2 is -1, not sqrt(i).
sqrt(i) is actually a complex number, equal to cos(45`) + i*sin(45`)

>>679278379
>http://www.mathplanet.com/education/algebra-1/exploring-real-numbers/square-roots
Anon, you didn't read it carefully. All positive numbers have 2 square roots, but see, the square root symbol is used to denote the positive square root. so sqrt(25) = 5. If you want the other square root, you say -sqrt(25).
And like mentioned in the article, if you want to say both squareroots of a number, you write it as +/-sqrt(25).
The square root function that we use in mathematics, and the one in the OP always is the principal square root of the number inside

>>679278381
Trig doesn't really have place in this equation. i doesn't come into place unless √(-x). For instance. √(-25) = 5i. Stop over thinking.

>>679278727
Fuck. You got me. God damn troll math.

X = (-24)

>>679278787
>Trig doesn't really have place in this equation
anon, all of math is interrelated. complex numbers and trig go hand in hand.

>√(-25) = 5i
That's right, but i came into place because you mentioned it - √(25i). What made you think √i = -1? That is not true at all.

>>679279051
Nah anon, sometimes the notation in math can lead to confusion, even to mathematicians.

>>679258904
J is engineering because I is designated for current t

>>679257422
Its unpossible doofus

>>679257422
No solution.

>>679265364
>Let's see who passed intro algebra.

Were done here

>>679279584
>>679280129
x= (-24)

>>679276103
>OP didn't state that x>0,
Yes he fucking did, you must have missed the part where there wasn't a negative before the square root. Fucking autismos, I swear.

>>679280443
(7+5i) is not 2, cunt

>>679257422
What the fuck u guys are faggots!
BODMAS!!
x-1? No more like x - (1+7) since addition comes before subtraction. Fuck your guys are thick

>>679280684
X = (-24)
(-24) - 1 = (-25)
Square root of -25 = (-5)
(-5) +7 = 2

>>679257422
sqrt(x-1) + 7 = 2
sqrt(x-1) = -5
(sqrt(x-1))^2 = (-5)^2
x-1 = 25
x = 26

Is this even fap worthy?

>>679281098
fuck off faggot, don't spew nonsense.
clearly according to BODMAS, = has higher priority, so first you do 7 = 2, the answer being NO, and then sqrt(x-1) + NO which is 4pi.

>>679281171
this shit gave me cancer

>>679281098
Addition and subtraction have the same priority in order of operation. Same with multiplication and division. You process them in the order they appear.

>>679281171
>Square root of -25 = -5
no, square root of -25 = 5i, you meat calculator

>>679281171
-5*-5 is positive 25. The square root if a negative number is imaginary, generally used by the placeholder "i"

You're still correct though, because the equation becomes
i+7=2, which is the same thing as -5. But it SHOULDN'T be, because math is an asshole.

since every square root has two solutions, both the positive and the negative, this problem also has two solutions.

x = [26,no solution]

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>>679281171
Is this like the scientology equivalent of math? what the actual fuck?

>>679282224
>scientology equivalent of math
kek

>>679281740
>>679281943
>>679282028
>>679282224
ok thats just how i saw it, i guess im pretty dumb

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>>679257422
fuck you fuckers are fucking retarded

sqrt(x-1) + 7 = 2
sqrt(x-1) = -5
sqrt(x-1) = 5 ( i ^ 2)
[sqrt(x-1)] / [ i ] = 5 i
[sqrt(x-1)] / [sqrt (-1)] / 5 = 5 i
[sqrt(x-1)*sqrt(-1)] / [sqrt (-1) * sqrt (-1)] = 5 i
>taking the top and bottom sqrt times the sqrt of -1
[sqrt(x-1)*sqrt(-1) / -1 = 5 i
sqrt (1 - x) = - 5 i

sqrt (1-x) = -5i

you can play around with it, but ultimately, you're going to have an imaginary solution
>no real solution, but in theory, an imaginary one

>>679283160
There is no solution at all.
Not a real one.
Not an imaginary one.
NO solution.

>>679283264
>Not an imaginary one

not sure if you know what "imaginary" means

>>679283264
>>679283688

if you define alwekng as
>alwekng = -5i
then x = 1 - (alwekng)^2

>>679283264
There is only the final solution.

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>>679257422
x = Kobe

>>679283819
>alwekng
what is this arbitrary mumbo jumbo

you fucking kids and your psuedo-math. You've still yet to prove there is a solution, maytee

>>679257687
cancerous faggot. the square root always has 2 solutions for real numbers: positive and negative.
>except for sqrt0

>>679284005

i mashed the keyboard, dumbass. you expect me to take the time to think of something for you?

>you still don't understand what an imaginary number is

>>679284021
You have no idea what you're talking about. Go to bed. Unless you're a yuropoor, in which case, please overdose on something.

x=78549023448

but not 100% postivie, i'm a bit drunk

.

>>679284324

but that is rounded to the nearest wole number.

rum+sleeping pille = groggyi

.

selec all of the pickup truks

>>679284249
In your 129 words and ~700 characters, you have not proven your point. At this point it's just damage control. Stop posting, nigglet.

>>67928402

Don't know if troll or just ignorant

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Choosing a proper sheet for the square root, x = 1+25 e^(2\pi i) works.

It looks like most of /b/ hasn't taken elementary complex variables.

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>>679283819
You call that a solution?

>>679284249

the reason i (the square root of negative 1) exists is to introduce a set of non-real numbers to satisfy the needs or theoretical equations. the number i is completely useless. just like my keyboard-mashing alwekng is useless. number i exists for no reason other than to satisfy the theoretical quantity of x^2=-1.
>theoretical quantity
>does not exist
>made up for no reason other than to satisfy a theoretical (non-existent) equation
x^2=-1 will never exist in real life. OP's equation will never exist in real life.

it's like taking a gun and turning it into a sheet of metal. The sheet of metal is useless, but it has potential to be turned back into a gun later on. Just like the number i can be multiplied by itself to give you -1 again.

>>679257422
x= -46

>>679284867
So, what's your point? It's certainly for your sake not a shoddy proof of a complex solution, I hope. Come back when you have something worth posting.

>>679284867
shut up kid

negative numbers "will never exist in real life" by your logic