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Could I prevail upon someone here for help in finding a derivative?

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Anonymous
Could I prevail upon someone here for help in finding a derivative? 2016-06-30 19:38:57Post No. 149100
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Could I prevail upon someone here for help in finding a derivative? Anonymous 2016-06-30 19:38:57 Post No. 149100 [Report]
Good people of /wsr/, please help a retarded philosophy major solve this problem.
>>
Anonymous 2016-06-30 20:45:01 Post No.149127
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Anonymous 2016-06-30 20:45:01 Post No.149127 [Report]
>>149100
Little rusty.
Can be reduced to (sec(q)/csc(q)) + 1
reduced more to (sin(q)/cos(q)) + 1
reduced more to tan(q) + 1
dp/dq = sec^2(q)
C
>>
Anonymous 2016-07-01 03:54:53 Post No.149284
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Anonymous 2016-07-01 03:54:53 Post No.149284 [Report]
This website: http://www.wolframalpha.com/input/?i=der+of+(secx%2Bcscx)%2Fcscx
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