Bout tree fiddy

50°

Are those β angles meant to b equal? Because that's a shitty diagram nigga

tbqh I gave up

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>>8091796

>>8092214

you what

The ones who said 50° are correct

>cant solve this despite knowing cosine and sine rules

Am I a brainlet? where is this from?

>>8092222
first of all, nice quads.
second of all, kinda tired so there. that's the answer.
x=50°+alpha-beta

ps: alpha and beta are equal aren't they?

>>8092214
[math]\alpha = \beta[/math] so you can simplify that to [math]50^ \circ[/math]

>>8092234
All you need to know is the sum of the interior angles of a polygon and basic algebra

>>8092246
Didn't save my scratchwork but you can show they're equal

>>8092247

I know what I need to solve it, but I can't work out what I need to do to arrive at the answer.

>>8092253
>>8092247
neat! i might redo this thing later then

can somebody post a proof please

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peanuts

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>>8092470

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>>8092470
continued

>>8092492
ah nice, this one is more elegant than my solution >>8092498

finding beta took me forever, the misleading measurements of the drawing really threw me off

>>8092470
>>8092492
Why did the signs swap from 130+b-a to 50-b+a for the x angle

Anyone know where I can find more problems like this?