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how does h approach zero such that we get derivatives? if we can't have it be


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how does h approach zero such that we get derivatives? if we can't have it be zero, how do we get a function which outputs every value of the instant change of y/x?

i know i'm stupid. i apologize for that. but i will not give up.
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>>7965758
you should revise the formal definition of the limit to get a better picture of what it means for h to approach 0
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>>7965758

Because we're looking at the limit as [math]h \rightarrow 0[/math]
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>>7965758
Are you that guy from before who kept talking about atoms and denying the concept of limits?
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You are "approaching" zero, you never actually arrive at zero.
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Basically you're approaching zero getting infinatly close, which means we can for all intents and purposes it is zero...even though it isn't actually zero.
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>>7966554
>intents and purposes it is zero

Pre calc babby detected?

Have you ever heard of the expression 0/0 being undefined?

Well, riddle me this batman, what is exactly happening when you cancel all the h's when you are derivating using the limit.

If your pre-calc class is good enough and you are able to answer me that question then congratulations, you have realized that no, for all intents and purposes it is NOT zero.
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