see pic
>>7749549
Mathfag false flag propaganda to antagonise engineers in major politics threads.
Very clever mathfags. Very clever indeed.
X/0 is not a valid expression.
>>7749549
4=4
2^2 = 4 and (-2)^2 = 4
2^2 = (-2)^2
2 = -2
2 + 2 = -2 + 2
4 = 0
4/2 = 0/2
2=0
>>7749552
why not?
>>7749552
https://en.wikipedia.org/wiki/Wheel_theory
>>7749562
nice post
>>7749557
x = y does not imply sqrt x = sqrt y
but sqrt x = sqrt y => x = y
>>7749568
prove it
>>7749558
let x/0 be a valid expression. Then 1/0 is the inverse element to 0, hence 0/0 = 1. Furthermore, 0/0 * a = (0*a)/0 = 0/0 = a for all a. Henceforth a=b for all a,b therefor the set of numbers only contains the number 0.
Not very useful huh?
>>7749568
That's not the issue with the proof, it's that the square root of a x^2 is defined to be |x|.
Of course if x=y then sqrt(x)=sqrt(y)
>>77495761
clearly it doesn't, for 2^2 = (-2)^2, but sqrt(2^2) =! sqrt((-2)^2)
>>7749570
let x = (-1)^2 and y = 1
qed
>>7749549
Here's the other version.
Can you nerds find any more?
>>7749549
i get it, that is why 0/0 is impossible.
>>7749549
And that is why dividing by 0 is considered undefinable. Math isn't magic, faggot.
>>7749649
is not undefinable if you take limits, however 0/0 is
>>7749562
I understand this like as 0x1, 1+1, 1x1 is the simplest arithmetic for real numbers
the opposite is the case for imaginary numbers 0x, x-x, x/x
this duality is beautiful
>>7749683
yes, because you're approaching the number, not assuming x = a
>>7749549
> mathematics = engineering
>>7749558
Defined as such in the field axioms.
Can't divide by zero in Q, R, C, or any other fields.
>>7749987
No, engineers are people who drive trains on the railroad.
>>7750077
engineers are people who work on engines
Lrn2engine
>>7749740
>dress something in a different name
wat
prove me wrong
>>7749549
Hey Opie
[eqn] 0 \cdot 4 = 0 \cdot 3 \\
4 = 3 [/eqn]
>>7750288
sqrt(x^2)=|x|
>>7750288
4 - 9/2 does not equal sqrt((4 - 9/2)^2)
remove screwdriver, god is a mathematics
