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You are currently reading a thread in /sci/ - Science & Math

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guys right now I'm writing finals in my University, so can you help me solve some of the easy math problems? So here is one of them for example
>>
6. We have [math]\displaystyle p(x) = g^2(x)f(x)[/math]. So [math]\displaystyle p'(x) = 2g(x)g'(x)f(x) + g^2(x)f'(x)[/math] which implies [math]\displaystyle p'(-1) = 2g(-1)g'(-1)f(-1) + g^2(-1)f'(-1) = 2(3)(5)(4) + (3)^2(1/3) = 123[/math]
>>
>1.
[eqn]\lim_{x \to 4^-} \frac{x-4}{x^2+x-20} = \lim_{x \to 4^-} \frac{1}{x+5} = \frac{1}{4+5} = \frac{1}{9}[/eqn]

A. 1/9


>2.
[eqn]\lim_{x \to \pi^+} \frac{x\cos(x)}{\sin(x)} = \lim_{x \to \pi^+} x\cos(x) \times \lim_{x \to \pi^+} \frac{1}{\sin(x)} = \pi\cos(pi) \times \frac{1}{\sin(\pi)} = -\pi \times -\infty = \infty[/eqn]

D. [eqn]\infty[/eqn]


>3.
[eqn]\lim_{x \to 2} \frac{\ln{(x^3-7)}}{4-x^2} = \lim_{x \to 2} \frac{\frac{3x^2}{x^3-7}}{-2x} = \lim_{x \to 2} \frac{-3x}{2(x^3-7)} = \frac{-3 \times 2}{2(2^3-7)} = -3[/eqn]

C. -3


>4.
[eqn]\lim_{x \to \infty} \frac{x^2}{4-x} + x = \lim_{x \to \infty} \frac{-4x}{x-4} = -4[/eqn]

D. -4


>5.
[eqn]f(x) = \frac{e^{2x}}{5+e^{4x}}\\
f'(x) = \frac{(5+e^{4x})2e^{2x} - (e^{2x}4e^{4x})}{(5+e^{4x})^2}\\
f'(x) = \frac{10e^{2x} - 2e^{6x}}{(5+e^{4x})^2}\\
f'(0) = \frac{10e^{0} - 2e^{0}}{(5+e^{0})^2}\\
f'(0) = \frac{10 - 2}{(5+1)^2}\\
f'(0) = \frac{8}{36}\\
f'(0) = \frac{2}{9}[/eqn]

B. 2/9


>6.
[eqn]p(x) = g^2(x)f(x)\\
g(-1) = 3, g'(-1) = 5,f(-1) = 4, f'(-1) = \frac{1}{3}\\
p'(-1) = f'(-1)g^2(-1) + 2g(-1)g'(-1)f(-1)\\
p'(-1) = (\frac{1}{3} \times 9) + (2 \times 3 \times 5 \times 4)\\
p'(-1) = 3 + 5!\\
p'(-1) = 3 + 120\\
p'(-1) = 123[/eqn]

D. 123


The only reason why I did this is because I want to practice my Calculus as well. This shit was extremely easy, though.
>>
multiple choice maths exams what in the fug
>>
>>7722137

what kind of backwater swamp of a university do you attend?


or you sure its not TAFE/community college?
>>
>>7722137
>>7724160

i mean its solving limits so the guys is in first year, first semester maths

still when i was in first year i never saw a multiple choice or take home exam, all our shit was invigilated

maybe its a course by correspondence so its all online work?
>>
>>7722137

Holy shits are these even called Exams?
>>
I fucking hate limits and all that is associated with them
I still don't get the point of derivatives
Why am I so retarded
>>
>>7724367
Yeah
>>
>>7724367
Derivatives are useful for tons of things. One common example is for approximation. Let's say you want to approximate (estimate) sqrt(3), but you don't have a calculator or anything on you. You could use derivatives for that:
[eqn]f(4-1)\approx (f'(4)\times-1)+f(4)\\
f(3)\approx f(4)-f'(4)\\
f(3)\approx 2-\frac{1}{4}\\
f(3)\approx \frac{7}{4}[/eqn]
You can also use derivatives to graph a function by hand (when you're given only the function, a pencil, and paper; no graphing calculator whatsoever). Derivatives can be used to find the velocity, acceleration, jerk, etc. of an object. Many basic physics formulas are actually from derivatives, such as ΔX = Vt + 0.5*a*t^2 is actually found and proven through derivatives, etc.

Meanwhile, we can use limits for a variety of different reasons. Limits can also be used to find derivatives; in fact, the linear approximation equation stems from the limit definition of the derivative of a function. Limits can be used to find antiderivatives as well, and we can use limits to find the area under a curve (aka definite integrals. It might seem petty, but to give you an example, in Statistics, the probability(s) in Normal Distributions are approximated through definite integrals.
E.g. For a normal distribution with μ = 0 and σ = 1, p(x <= -1):
[eqn]p(x \leq -1)=\int_{-\infty}^{-1} \frac{e^{-\frac{x^2}{2}}}{\sqrt{2\pi}}\\
p(x \leq -1) \approx 0.158655...[/eqn]
Yep. Limits can literally be used to find the probability of event(s) happening. Limits can also be used to find indefinite integrals (a.k.a. no bounds). There are a variety of other uses for integrals and derivatives that I am probably missing out on, but I hope you get the point.

They're important.
>>
>>7725627
That second Tex equation came out a bit funky... let me try again (and if this doesn't work then I give up. Just plug it into a Tex editor to view if you're curious):

[eqn]
p(x \leq -1) = \int_{-\infty}^{-1} \frac{e^{-\frac{x^2}{2}}}{\sqrt{2\pi}}\\
p(x \leq -1) \approx 0.158655...
[/eqn]
>>
>>7725627
>>7725635
...And I forgot to add dx for the integral. Fuck. Just pretend it's there.

[math]
p(x \leq -1) = \int_{-\infty}^{-1} \frac{e^{-\frac{x^2}{2}}}{\sqrt{2\pi}} dx\\
p(x \leq -1) \approx 0.158655\ldots
[/math]
>>
A lot of this stuff doesn't seem too different from trig. I thought math was supposed to get more fun after trig.
>>
File: 1444966794905.jpg (31 KB, 352x450) Image search: [Google]
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Why did your teacher put brackets on #4 OP? It seems a bit redundant and is pissing me off, frankly.
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>>7725853
because there are two terms in that one, so we want to make sure the "+x" is included in the limit calculation
>>
>>7722137
you are writing the exams? so you are the professor? and you don't know calculus?

remind me not to go to your school!
>>
>>7722137
R u srs
>>
>>7725853
That's proper notation
>>
>>7725879
>>7725915
Yeah I got that but I always thought since high school, that it's implied through the expression that it applies everywhere.
>>
This is a bait, you are solving his exam.
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