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Le Mathematique
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You are currently reading a thread in /wsr/ - Worksafe Requests

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How in the hell do you go from the first line to the last, im bamboozled beyond measure.

Thanks In advance
>>
>>82167

(2/3)x(x+1)^(3/2) - (4/15)(x+1)^(5/2) + c

>find common denominator and split (x+1)^(5/2) using properties of exponents
= (10/15)x(x+1)^(3/2) - (4/15)(x+1)^(2/2)*(x+1)^(3/2) + c

>find common factor between two terms (highlighted using square brackets)
= [(2/15)(x+1)^(3/2)]*5x - [(2/15)(x+1)^(3/2)]*2(x+1)^(2/2) + c

>factor
= (2/15)(x+1)^(3/2) * (5x - 2(x+1)^(2/2)) + c

>2(x+1)^(2/2) reduces to (2x+2)
= (2/15)(x+1)^(3/2) * (5x - 2x - 2) + c

>simplify and rearrange
= (2/15)*(3x-2)*(x+1)^(3/2) + c
>>
>>82195
Not OP but was curious about the question as well because it's been a damn long time since I've done this sort of math

Thanks, anon
Thread replies: 3
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