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How would one go about evaluating the limit of pic related?
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Anonymous
2016-02-11 14:57:35 Post No. 54802
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Anonymous 2016-02-11 14:57:35 Post No. 54802 [Report]
How would one go about evaluating the limit of pic related?
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Anonymous 2016-02-11 15:04:15 Post No.54804
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Anonymous 2016-02-11 15:04:15 Post No.54804 [Report]
>>54802
The exponents are the same so the solution should be -sqrt(x)/sqrt(x) = -1
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Anonymous 2016-02-11 15:10:25 Post No.54808
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Anonymous 2016-02-11 15:10:25 Post No.54808 [Report]
>>54804
But the 6's cannot cancel, correct? So what happens to the 6's?
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Anonymous 2016-02-11 15:29:32 Post No.54818
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Anonymous 2016-02-11 15:29:32 Post No.54818 [Report]
>>54808
As x tends towards infinity, sqrt(x) gets very, VERY large. Infinitely large, in fact. Adding a constant (like 6) to an infinitely large number really makes no difference in the result, so in the case of this limit, the 6s can be ignored.
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Anonymous 2016-02-11 15:32:55 Post No.54822
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Anonymous 2016-02-11 15:32:55 Post No.54822 [Report]
Okay, that makes sense. Thank you guys/gals.
>>54818
>>54804
Thread replies: 5
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