-2(x-5)^3+3
http://www.projectsharetexas.org/node/3005
hey b, If I were to transform this function.
-2(x-5)^3+3
what order would I do it, would I do the parameter a, h or k?
Also does order matter when transforming a function?
Please help me
y=a(x-h)2+k
this is the base
>y = a(x-h)^2+k
You start with the function y = x^2.
y = (x-h)^2 shifts the graph h units to the right (if h > 0) or to the left (if h < 0, that is, in this case you add a positive number to x).
y = a(x-h)^2
Here you stretch the previous graph in direction of the y-axis by a factor of a. If a = 2 all function values are twice as big, if a = 0.1 then the function values are divided by 10, and so on. If a < 0 then you also reflect it on the x-axis.
y = a(x-h)^2 + k
Here you translate the previous graph k units in direction of the y-axis if k > 0.
>y = -2(x-5)^3+3
here you have a cubic function, but the same principles apply.
You have the graph of the function y = x^3 moved to the right by 5 units, stretched by a factor of 2, reflected on the x-axis and moved up by 3 units.
>>43380
Take note that the text in that page uses y=a(x-h)^2+k but the interactive example y=a(x+h)^2+k
