I need help. How do I find the x-int for number 12?

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Anonymous
2016-06-15 18:37:25 Post No. 140995
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Anonymous 2016-06-15 18:37:25 Post No. 140995 [Report]

I need help. How do I find the x-int for number 12?

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Anonymous 2016-06-15 18:40:50 Post No.140998
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Anonymous 2016-06-15 18:40:50 Post No.140998 [Report]

>>140995
For the y-intercept, set x=0, calculate y.
For the x one set y=0.

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Anonymous 2016-06-15 18:43:40 Post No.140999
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Anonymous 2016-06-15 18:43:40 Post No.140999 [Report]

>>140998
Should be 16 if I'm not mistaken

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Anonymous 2016-06-15 18:44:51 Post No.141001
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Anonymous 2016-06-15 18:44:51 Post No.141001 [Report]

>>140998
I don't know where to go from there though. Should I move 3x+1 to the other side by multiplying? But then I would be multiplying by 0

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Anonymous 2016-06-15 18:48:02 Post No.141002
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Anonymous 2016-06-15 18:48:02 Post No.141002 [Report]

>>141001
Yup, multiply by 3x + 1.
You get 4=sqrt(x), which, after squaring, becomes x=16

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Anonymous 2016-06-15 18:49:01 Post No.141004
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Anonymous 2016-06-15 18:49:01 Post No.141004 [Report]

>>141001
>But then I would be multiplying by 0
all the better :-) so you can completely ignore the denominator

0*(3x+1) = 4-sqrt(x)
0 = 4-sqrt(x)
sqrt(x) = 4

or in other words: x = 4^2

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Anonymous 2016-06-15 18:50:28 Post No.141005
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Anonymous 2016-06-15 18:50:28 Post No.141005 [Report]

>>141002
>>141004
Thanks (: