Can /lgbt/ solve a simple math problem? I know there's an abundance of /STEM/ mtf trannies on here so you guys shouldn't have any issues.
30? Is this even a question?
I'm assuming 10 is the entire hypotenuse btw.
Why does this require any STEM knowledge at all?
>>6144500
I guess "stem" means your brain stem is intact?
40.8
The inner triangles are similar, so the bit colinear to 10 is 6*6/10
Everything 1/2 baseXheight
>>6143630
>>6143630
it's (6*10)/2.
It almost made me think a bit. Drawing it would be harder though, but doable.
>>6143630
NO
GET OUT
We just got 350 posts of trolling on /fit/
REPORTED
REEEEE
>>6144712
>>6144649
>>6144500
baka such triangle cannot exist. At most the altitude is 5.
>>6144831
>Not calling the OP out for presenting impossibilities
>>6144649
The inners are not similar because they fail the AA, SSS and SAS similarity theorems. This is something you should be able to recall from geometry.
These
30i * sqrt(46)
>>6145314
wait i multiplied the bases and not base and height nevermind
Here is a trick one I don't think anyone will get at first try
1+2+3+...= ?
And then prove it.
K we have a right angle so A^2 + B^ = C^2
A=10 - X
B= 6
(10-X)^2 + 36 = C^2
X^2 - 20X + 100 + 36 = C^2
sqrt (X^2 - 20X + 136) = C -> We'll note this as Y
This is bottom side of our triangle.
Left side is: A^2+B^2 = 36 + X^2 = C^2
sqrt (36+X^2) = C -> We'll note this as Z
That's the left side of the triangle.
These two can relate in the full triangle since we just did the 2 halves.
Z^2 + Y^2 = 10
X^2 - 20X + 136 + X^2 + 36 = 10
2X^2 - 20X + 126 = 0
We can solve this with the quadratic equation simply for X.
[-b (+/-) sqrt(b^2 - 4ac) /] 2a = [20 (+/-) sqrt(400 - 4 * 2 * 126) ] / 2*2
20(+/-) sqrt(-608) / 4 = 20 (+/-) sqrt(608i) / 4
reduce the 608 to something simplar
608 = (38 * 16)
Thus we can reduce the rest
20(+/-) 4 sqrt(38i)/4 -> 5 + 4sqrt(38i) or 5 - 4sqrt(38i)
Yes, with the i's and everything. As you'll note, this triangle has imaginary numbers involved in X, and neither make sense.
Your base of triangle is thus going to be imaginary, and the bottom, and each will have 2 possible answers due to the results of the quadratic equation, but both possible answers are IMAGINARY. Just like OPs friends.
>Stem tranny here.
>>6148492
Just realized something and will copy paste.
>Z^2 + Y^2 = 10
>FAILED HERE AND AFTER RIP, Redoing
Z^2 + Y^2 = 100
X^2 - 20X + 136 + X^2 + 36 = 100
2X^2 - 20X + 172 = 100
2X^2 - 20X + 72 = 0
Now Quadratic Equation this shit
20 (+/-) sqrt(400 - 4 * 2 * 72) / 4 = X
20 +/- sqrt(-176) / 4 = X
20 +/- sqrt (-16*11) / 4 = 5 (+/-) sqrt(11i) =X
Since 5+sqrt(11i) or 5-sqrt(11i) is the value for X, the extra segment, triangle is again imaginary. RIP me.
>>6145420
-1/12
>>6145420
>MUH DEALING WITH INFINITY AS A NUMBER FORMULAS
I don't think a right angle triangle with such proportions can exist...
A right angle triangle exists where it's three points touch the circumference of a circle. If the diameter of the circle is 10 then I think the altitude can be at most 5 to remain a right angle triangle? Sorry I'm not very good at maths...
>>6145420
1+2+3+...=6...
>>6149315
This answer made me laugh.
>>6145420
I'm the bazinga guy. Just had to reply one more. I don't understand why this maths "trick" is popular and I don't understand why it has its own wiki page. I'm not an academic in maths, but I am a PhD in CompSci and it is conceptually wrong. Infinity is a concept and you're trying to do finite sums to infinite numbers.
>>6149842
It's an identity. There might be some youtube videos about how to work it out and prove it. There are lots of things in real math that don't make sense to laymen or even associated fields. The issue might be that you consider it as an arithmetic problem.
>>6149890
That's just silly. You can use infinite series to "prove" whatever.
"In fact, you can derive all sorts of results messing around with infinite sums that diverge. It’s a trick! "
(https://plus.maths.org/content/infinity-or-just-112)
Given enough time, you can end up with another result for 1 + 2 + 3 + \dots. So what is it then, like say 200 = -1/12? Then what? It's a conceptually flawed question from the beginning.
>>6149890
Exactly as this guy says.
<<"Knowing they had the analytic continuation method, that would make the final result OK, hidden in their back pocket, they went ahead with their sleight of hand. In doing so they got over a million hits and had the world talking about zeta functions and mathematics. For this they should be congratulated. "
I think spreading ignorance will rather attract ignorant fan-boys and repel those with rational reasoning.>>
I thought the STEM MTF thing was just a meme. Huh. But I'm a humanities FTM so what the fuck do I know.
>>6150364
Oh my god. Humanities are largely dominated by women, and STEM by men, and apparently its just the opposite among trannies?
>>6150460
I'm FtM and majoring in maths, I didn't think it would be common for others to major in humanities type shit.
>>6150460
it's due to socialization n shit
>>6150460
I'm ftm and dual majoring english and econ, but only because I'm not dumb enough to get an english degree by itself. With the trans guys I know it's pretty balanced between the two, maybe a little more compsci/math, but that's anecdotal anyway.
>>6150364
MTF in humanities, but we could just be minor variations in a bigger trend.
>>6151058
Someone make a strawpoll
>>6143630
A right triangle can't have an altitude to its hypotenuse greater than 1/2 of the hypotenuse. Regardless, a triangle with a side of 10 and an altitude from that side of 6 has an area of 30.
>>6144831
>>6148492
>>6148502
>Assuming euclidean geometry
plebs
