Batman (mass 80.0 kg) stands on a window ledge 5.0 m above the floor (Fig. 8-40). Grabbing a rope attached to a chandelier, he swings down to grapple with The Joker (mass 70.0 kg), who is standing directly under the chandelier. (Assume Batman’s center of mass moves down 5.0 m. He releases the rope just as he reaches The Joker.)
a) With what speed do the entwined foes start to slide across the floor?
b) If the coefficient of kinetic friction of their bodies with the floor is μ = 0.250, how far do they slide?
>>80684375
Anon...stop. This isn't /m/ or /tg/, this is /co/, and /co/ hates math and science. Hell even /a/ has talks on subjects of math every blue moon.
>>80684375
Bump
>>80684375
Ka-pow! With a remainder of Thwack!
>implying Batman will entwine with the Joker and not simply kick him square in the chest and flip to land standing over him
Delta in gravitational potential = kinetic energy
=> v = √(2gh)
Opposing force due to friction = mass * acceleration due to gravity * coefficient of friction = -mass * acceleration
=> A = -μg
Time to stop = speed / acceleration in negative direction
=> t = √(2gh)/μg
Plug this into the kinematic equation v*t + 1/2*a*t^2 = d, remembering that a is in the opposite direction to v
It should work out to d = h / μ , or far fewer meters than the number of lives batman could save if he'd just shoot the joker and finally get it over with.
>>80684375
Why doesn't he just throw a battarang?
>>80684375
>Batman only weighing 175
>Joker weighing as much as 155
'no'
>>80684375
>muh realism.
Go away.
>>80685424
Uh... let's just assume that the Joker has no mass.
>>80684375
Do your own homework
>>80684826
>not twining thine limbs about thy most worthy foe's heated flesh
>>80685531
Batman, with the Nolan suit on, would weight 225+ easily.
Joker, eh...I could see him as a solid 175+.
>>80684375
>Batman (mass 80.0 kg)
Sure, let's ignore the mass of his equipment! That's how you get people killed, you maniacs!
>>80686058
batman weighs 240 pounds and is 6'3", same as me.
To find out how fast Batman is going, first we have to know his speed. To do this, we transfer all the gravitational potential energy he has, or the energy an object has when suspended above the Earth, to kinetic energy.
1 g = 9.81 m/s2
So, at 5 meters above the ground, a 80 kg Batman (no way he's that light, especially with all the armor on) has 3,924 J of potential energy.
Potential energy then becomes kinetic energy.
1/2*mass*velocity^2, i.e. 9.9m/s.
With an 80kg Batman moving at 9.9m/s, the 150kg Batman & Joker pair should begin skidding at 5.3m/s.
The rest is obvious.
>>80684375
I get the feeling that the chandelier is not staying up.
>>80684375
bump
For that answer we need to know the angular speed and thus we need to know the distance of Batman's rope
![4740655-0875727850-riddle[1].jpg](https://i.imgur.com/XBSBFPy.jpg "4740655-0875727850-riddle[1].jpg")
a) 5.28
b) 5.7
>>80684809
You cheeky cunt.
>>80684375
Batman shatters the Joker's ribs into splinters and the Joker sputters on the ground as he dies of two punctured lungs.
